Answer:
5.4 in.
Step-by-step explanation:
Figuring out the area of shapes like these are quite simple, you first have to break apart this shape to make solving this easier. If you draw a line and break off the triangle from the square you will get 2 different shapes. A square with all the sides being 2 inches, and a triangle that is 2 inches tall and 1.4 inches across (you subtract 3.4 by 2). Next you just use the equation (2 * 2) + ((1.4 * 2)/2). Multiply 2 by 2 (which is 4) and you get the area of the square (you multiply the base by the width). And for the triangle you multiple 1.4 by 2 (you get 2.8)... But because it's a triangle you have to divide that number by 2 since the triangle is half of a square. So 2.8 / 2 is going to be 1.4. After that you now have the equation 4 + 1.4 and the answer is going to be 5.4.
Answer:
-13/20
Step-by-step explanation:
-0.65=-65/100
=13/20
Wait what's the question tho?
is it if this point is on the line?
cause it's not
-y=mx+b
3=-6(6)-3
-3=-36-3
-3 does not equal -39
hence, point is not on the line
Answer:
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
Step-by-step explanation:
For n=6 the degrees of freedom will be n-1 = 5 .
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
The critical region depends on ∝ and the alternative hypothesis
a) When Ha is σ²≠σ² the critical region is
χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test
( χ² < 0.83) and ( χ² > 0.83)
b) When Ha is σ²> σ² the critical region falls in the right tail and its value is
χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}
c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value
χ²(1-∝)(n-1) One tailed test (1.145)
