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Sedbober [7]
2 years ago
13

Can Someone Explain? The Question Is In The Picture!​

Mathematics
1 answer:
Amiraneli [1.4K]2 years ago
8 0

(256)^{\tfrac 14}\\\\=(4^4)^{\tfrac 14}\\\\=4^{\tfrac 44}\\\\=4^1 \\\\= 4\\\\\\27^{\tfrac 13}\\\\=(3^3)^{\tfrac 13}\\\\=3^{\tfrac 33} \\\\=3^1\\\\=3

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Michael has 5 boxes. There are 5kg of apples in each box. When empty, a box weighs 5-2 kg.
Sphinxa [80]
As I understand from the given above, each box when empty weighs 5-2 kg or 3 kg. To determine the total weight of Michael's boxes when empty, we just have to multiply 3 kg by 5. This gives us an answer of 15 kg. Thus, the total mass of Michael's boxes is 15 kg. 
3 0
3 years ago
The perimeter of a rectangular garden is 52 feet the length of the garden is 4 less than twice the width what is the widththe
GaryK [48]
W= Width 
L= Length

2L+2w=52
2W-4=L
Plug in L into the first equation
2(2W-4)+2w=52
4w-8+2w=52
6W=60
W=10 feet
Plug that into the second equation
2(10)-4=L
L=16
4 0
3 years ago
You are working on a proof. You know that A and B are on the perpendicular bisector of CD. What can you conclude? A) AC = BD B)
MatroZZZ [7]
You can only conclude that AC = AD  

Its C
5 0
3 years ago
ABC is an isoscles triangle. Angle A = 40°.
umka21 [38]

Answer:

70 degrees

Step-by-step explanation:

total angle in a triangle is 180 degrees

180-40= 140

Angle b and c is total of 140 degrees

they are isosceles so their measurements would be same.

angle b and c is 140÷ 2 = 70

so angle b is 70 degrees

8 0
3 years ago
Which expression is equivalent to StartFraction 2 a + 1 Over 10 a minus 5 Endfraction divided by StartFraction 10 a Over 4 a squ
const2013 [10]

Answer:

\frac{(2a + 1)^2}{50a}

Step-by-step explanation:

Given

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

Required

Find the equivalent

We start by changing the / to *

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1}

\frac{2a + 1}{10a - 5} * \frac{4a^2 - 1}{10a}

Factorize 10a - 5

\frac{2a + 1}{5(2a - 1)} * \frac{4a^2 - 1}{10a}

Expand 4a² - 1

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1}{10a}

\frac{2a + 1}{5(2a - 1)} * \frac{(2a)^2 - 1^2}{10a}

Express (2a)² - 1² as a difference of two squares

Difference of two squares is such that: a^2- b^2= (a+b)(a-b)

The expression becomes

\frac{2a + 1}{5(2a - 1)} * \frac{(2a - 1)(2a + 1)}{10a}

Combine both fractions to form a single fraction

\frac{(2a + 1)(2a - 1)(2a + 1)}{5(2a - 1)10a}

Divide the numerator and denominator by 2a - 1

\frac{(2a + 1)((2a + 1)}{5*10a}

Simplify the numerator

\frac{(2a + 1)^2}{5*10a}

\frac{(2a + 1)^2}{50a}

Hence,

\frac{2a + 1}{10a - 5} / \frac{10a}{4a^2 - 1} = \frac{(2a + 1)^2}{50a}

4 0
3 years ago
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