<span>We want to optimize f(x,y,z)=x^2 y^2 z^2, subject to g(x,y,z) = x^2 + y^2 + z^2 = 289.
Then, ∇f = λ∇g ==> <2xy^2 z^2, 2x^2 yz^2, 2x^2 y^2 z> = λ<2x, 2y, 2z>.
Equating like entries:
xy^2 z^2 = λx
x^2 yz^2 = λy
x^2 y^2 z = λz.
Hence, x^2 y^2 z^2 = λx^2 = λy^2 = λz^2.
(i) If λ = 0, then at least one of x, y, z is 0, and thus f(x,y,z) = 0 <---Minimum
(Note that there are infinitely many such points.)
(f being a perfect square implies that this has to be the minimum.)
(ii) Otherwise, we have x^2 = y^2 = z^2.
Substituting this into g yields 3x^2 = 289 ==> x = ±17/√3.
This yields eight critical points (all signage possibilities)
(x, y, z) = (±17/√3, ±17/√3, ±17/√3), and
f(±17/√3, ±17/√3, ±17/√3) = (289/3)^3 <----Maximum
I hope this helps! </span><span>
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When he cubed ,
Result is x³
On further squaring x³, he got = (x³)²
<h3>Therefore, k =
6</h3>
23400 x 8/100 = 1872 = the loss
1872 : 12 = 156= the loss each month
156/1872*100% = 8,33 % then round it
Answer:
k = 5
Step-by-step explanation:
given f(x) then f(x) + k represents a vertical translation of f(x)
• If k > 0 then a shift of k units up
• If k < 0 then a shift of k units down
f(x) crosses the y- axis at - 2
g(x) crosses the y- axis at 3
Thus g(x) is 5 units vertically up from f(x)
since g(x) = f(x) + k → then k = 5
Answer:
$29,900
Step-by-step explanation:
The computation of the balance of Work in Process as of April 30 is shown below:
= Opening balance of work in process + direct material cost + direct labor cost + factory overhead cost - goods finished
= $7,000 + $78,400 + $195,000 + $136,500 - $387,000
= $29,900
The direct material cost + direct labor cost + factory overhead cost is known as manufacturing cost
