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3 years ago

8

The temperature was 68°F. Later that day the temperature was 82°F. How much does the temperature need to rise or fall to return

to the original temperature 68°F

2 answers:

kati45 [8]3 years ago

8 0

Answer:

14

Step-by-step explanation:

if the original number is 62 and it goes up to 82 if you take 2 away from 82 it would be 80 the 80-12= 68

AVprozaik [17]3 years ago

3 0

Answer:

14 degrees farenheight

Step-by-step explanation:

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If point A is located at (-9, 2) on a coordinate plane, and point B is located at (-9, 10), what is the distance between the two

JulsSmile [24]

ANSWER

8 units.

EXPLANATION

The first point, A is located at (-9,2) on the coordinate plane.

The second point, B is also located at (-9,10) on the coordinate plane.

You should be smart and observe that the x-coordinates of both points are the same. This means that, the two points lies on a vertical line.

Hence it will be faster to use the absolute value method rather than the distance formula.

According to this method, you only have to find the absolute value of the difference in the y-values.

$|AB|=|10-2|$

$|AB|= |8| = 8units$

6 0

3 years ago

You a Miguel Cervantes de Navas y Colon, captain in the Royal Spanish Army in Seville in the year 1842. Outside your barracks wi

djverab [1.8K]

<u>650 cannonballs </u>

Explanation step by step:

upper layer = 1 ^ 2

second layer = 2 ^ 2

third layer = 3 ^ 2

layer 12 is 12 ^ 2

<u>The formula is: </u>

<u>n * (n + 1) * (2n + 1) / 6 </u>

<u>n = 12 </u>

<u>12 (12 + 1) (2 * 12 + 1) / 6 </u>

<u>12 * 13 * 25/6 = </u>

<u>650 </u>

<u> </u>

There are 650 cannonballs in this pyramid.

5 0

2 years ago

Read 2 more answers

If UV ≅ UX and WX=23, what is VW?<br><br> VW =

KiRa [710]

<h2>Answer: </h2>

The length of VW is 23°

<h2>Step-by-step explanation: </h2><h3>Known : </h3>

UV = UX
WX = 23

<h3>Asked : </h3>

VW = ?

<h3>Solution : </h3>

Since the UV line and UX line has the same length, so the VW line should have the same length as the WX line.

VW = WX

23 = 23

<h3>Conclusion : </h3>

The length of VW is 23°

5 0

2 years ago

Guys plz help me answer this!!!

ddd [48]

Answer: number 2

cuz its the only one that makes sense

5 0

2 years ago

The graph below represents the solution set of which inequality?

natulia [17]

Answer:

option: B ( $x^2+2x-8$ ) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

$x^2-2x-8$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8$

⇒ $x(x-4)+2(x-4)=0$

⇒ $(x+2)(x-4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x+2>0$ and $x-4$

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

$x+2$ and $x-4>0$

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

$x^2+2x-8$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8$

⇒ $x(x+4)-2(x+4)$

⇒ $(x-2)(x+4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x-2>0$ and $x+4$

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

$x-2$ and $x+4>0$

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

$x^2-2x-8>0$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8>0$

⇒ $x(x-4)+2(x-4)>0$

⇒ $(x-4)(x+2)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x+2>0$ and $x-4>0$

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

$x+2$ and $x-4$

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

$x^2+2x-8>0$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8>0$

⇒ $x(x+4)-2(x+4)>0$

⇒ $(x-2)(X+4)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x-2$ and $x+4$

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

$x-2>0$ and $x+4>0$

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.

5 0

3 years ago