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AysviL [449]
2 years ago
12

Find the volume of the figure. Round to the nearest hundredth if needed.

Mathematics
1 answer:
balu736 [363]2 years ago
6 0

Answer:

235.62 cubed yards

Step-by-step explanation:

Area of a cylinder = pi(r^2)*h

pi(5^2)*3 = 235.62

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A hiker maintains an average speed of 3 3/4 km/h. How many kilometers will the hiker walk in 5 hours
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Only the smartest person in their math class can help me with this difficult problem!!!
vodomira [7]

Step-by-step explanation:

\tt{(5 {x}^{3}  - 3x + 6) - (2 {x}^{2}  - 4x + 8)}

While subtracting , the sign of each term of second expression changes & remove the parentheses.

⟶ \tt{5 {x}^{3}  - 3x + 6 - 2 {x}^{2}  + 4x - 8}

Combine like terms. Like terms are those which have the same base. Only coefficients of like terms can be added or subtracted.

⟶ \tt{5 {x}^{3}  - 3x + 4x + 6 - 8 - 2 {x}}^{2}

⟶ \tt{5 {x}^{3}  + x - 2 - 2 {x}^{2} }

In standard from , the expression should be written in such a way that the power of variables goes from highest to lowest.

\red{ \boxed{ \boxed{ \tt{Our \: final \: answer :  \boxed{ \tt{5 {x}^{3}  - 2 {x}^{2}  + x - 2}}}}}}

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6 0
3 years ago
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The function f(t)=3,502.86(1.15)(t−12) models the amount of money in Gavin's investment account after t years. Gavin says this m
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Step-by-step explanation:

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While ( t - 12 ) tells us about the period of time.

And f(t) is the amount of money in Gavin's investment account after t years

8 0
3 years ago
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5. Can someone explain how to solve this?
zhannawk [14.2K]

Answer:

AC = 5 cm

BD = 12.5 cm (3 sf) [or 2 × root 39]

BE = 6.93 cm (3 sf) [or 4 × root 3]

Step-by-step explanation:

CE = 8cm [CE is radius of circle]

AC + 3 = 8

<u>A</u><u>C</u><u> </u><u>=</u><u> </u><u>5</u><u> </u><u>c</u><u>m</u>

BC = 8cm [BC is a radius of circle]

(AC)^2 + (AB)^2 = (BC)^2 [Pythagoras theorem]

25 + (AB)^2 = 64

AB = 6.2450 cm (5 sf) [or root 39]

BD = 2(BA)

= 2(6.2450)

<u>B</u><u>D</u><u> </u><u>=</u><u> </u><u>1</u><u>2</u><u>.</u><u>5</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>2</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>9</u><u>]</u>

(BA)^2 + (AE)^2 = (BE)^2 [Pythagoras theorem]

39 + 9 = (BE)^2

<u>B</u><u>E</u><u> </u><u>=</u><u> </u><u>6</u><u>.</u><u>9</u><u>3</u><u> </u><u>c</u><u>m</u><u> </u><u>(</u><u>3</u><u> </u><u>s</u><u>f</u><u>)</u><u> </u><u>[</u><u>o</u><u>r</u><u> </u><u>4</u><u> </u><u>×</u><u> </u><u>r</u><u>o</u><u>o</u><u>t</u><u> </u><u>3</u><u>]</u>

6 0
3 years ago
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