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stellarik [79]
3 years ago
14

Find the equation of the line that is perpendicluar to y=-2/3x and contains the point (4,-8)

Mathematics
1 answer:
suter [353]3 years ago
5 0

Answer:

Step-by-step explanation:

The slope of two perpendiculars is

m1*m2 = - 1

m1 = - 2/3

-2/3 * m2 = -1                      Multiply both sides by -3/2

-3/2 * -2/3 * m2 = -1*-3/2

m2 = 3/2

So far what you have is

y = 3/2 x + b

x = 4

y = - 8

-8 = 3/2*4 + b

-8 = 6 + b           Subtract 6 from both sides

b = - 14

Complete line

y = 3/2 x  - 14

The red line is y = -2/3x

The blue line is y = 3/2x - 14

The point (4,-8) is marked for you

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Answer:

B

Step-by-step explanation:

78x9=702

702/6=117 minutes.

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Value of x 9(2x-1)-9x - 18
bixtya [17]
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NEED HELP ASAP WILL GIVE BRAINLIEST REAL ANSWERS ONLY PLZ WILL REPORT FAKE ANSWERS
Contact [7]

Answer:

C

Step-by-step explanation:

There is a common ratio between consecutive terms

r = 24 ÷ 16 = 36 ÷ 24 = 54 ÷ 36 = 1.5 = \frac{3}{2}

This indicates the sequence is geometric with nth term ( explicit formula )

f(n) = a₁(r)^{n-1}

where a₁ is the first term and r the common ratio

Here a₁ = 16 and r = \frac{3}{2} , then

f(n) = 16 (\frac{3}{2}) ^{n-1} → C

6 0
2 years ago
A 150 no container can hold 23.6 g of aluminum what is the density of the aluminum?
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Answer:

# The density of the aluminum is 59/375 ≅ 0.157 g/cm³

# The volume of the container is 4/17 ≅ 0.235 cm³

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Step-by-step explanation:

* Lets explain how to solve the problem

- Density is a measurement that compares the amount of matter

 of an object to its volume [ Density = mass/volume]

- Density is found by dividing the mass of an object by its volume

- The unit of measuring density is gram per centimeter³ (milliliter)

* Lets solve the problems

# A container of volume 150 cm³ can hold 23.6 g of aluminum

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# The density of mercury is 13.6 g/cm³ at 23 C°

- A container can hold 3.2 g of mercury at this temperature

∵ Density = mass/volume

∵ The mass = 3.2 g

∵ The density = 13.6 g/cm³

∴ 13.6 = 3.2/volume

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∵ The density = 4.9 g/cm³

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