Find the equation of the line that is perpendicluar to y=-2/3x and contains the point (4,-8)
1 answer:
Answer:
Step-by-step explanation:
The slope of two perpendiculars is
m1*m2 = - 1
m1 = - 2/3
-2/3 * m2 = -1 Multiply both sides by -3/2
-3/2 * -2/3 * m2 = -1*-3/2
m2 = 3/2
So far what you have is
y = 3/2 x + b
x = 4
y = - 8
-8 = 3/2*4 + b
-8 = 6 + b Subtract 6 from both sides
b = - 14
Complete line
y = 3/2 x - 14
The red line is y = -2/3x
The blue line is y = 3/2x - 14
The point (4,-8) is marked for you
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Answer:
Step-by-step explanation:
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