The lengths of the sides of the triangle are 8, 8, 20
Explanation:
Given that the perimeter of an isosceles triangle is 36 inches.
The base of the triangle is 
times longer than each of its legs.
We need to determine the lengths of the sides of the triangle.
<u>Lengths of the sides:</u>
Let x denote the lengths of the sides of the triangle.
The base of the triangle is given by
Perimeter of the isosceles triangle = Sum of the three sides of the triangle.
Thus, we have,
Thus, the length of the sides of the isosceles triangle is 8 inches.
Base of the triangle = 
Hence, the three sides of the isosceles triangle are 8, 8, 20
Answer:
Step-by-step explanation:
1) ?
I can't see what that one given angle is .. but it's that mystery angle subtracted from 180 give the angle BOA then you know that's an isosceles triangle again that the BOA is part of... so then just subtract BOA from 180 to find the two other angle of that triangle... they are the small so just divide your answer of 180-BOA /2 is the angle of each.. then since you know those to smaller angles subtract one from 90 to find the angle BAX
2) ( as we would read normally)
You're making this really tough on me.. I can just barely read the equations
I think it's 1+6x and 7x-3 . b/c they are the same length sides you can set those equal
1+6x = 7x -3
4+6x = 7x
4 = x
that worked out well :
for the tangent.. it's Tan(Ф)= Opp/ Adj
but I don't know which side they want to solve for.. I think you may have left off some of the instructions???? :/
ohh I think they really mean.. what's the length of the tangent lines .. that was confusing to me.. :/ just plug in 4 into x for either eq.
1+6(4) = 25
or
7(4)-3=25
tangent is 25
3)
x-2 = 2x-10
x+8 = 2x
8 = x
again they made it work out easy :)
Then plug 8 into either equation to find the length of the tangent lines
8-2=10
tangent is 10
4) = 2) ??? they are the same question maybe you meant to put something else?
Answer:
s=25
Step-by-step explanation:
Solution:
Using Substitution Method:
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
get the value of x from Equation 2
x=3y-5 (Equation 3)
Put the value of x from Equation 3 in Equation 1
-4(3y-5)+7y=-5
-4(3y)+20+7y=-5
-12y+7y=-5-20
-5y=-25
Negative sign on both sides cancels each other
y=25/5
y=5
Putting value of y in equation 3
x=3(5)-5
x=15-5
x=10
Therefore, [x,y]=[10,5]
Using Elimination Method
-4x+7y=-5 (Equation 1)
x-3y=-5 (Equation 2)
Multiply equation 2 with -4 in order to eliminate the x term
-4(x-3y)=-5*4
-4x+12y=20 (Equation 3)
Adding Equation 1 and 3
-4x+7y=-5
-4x+12y=20
+ - = - (Change Of Sign with x and y terms)
-----------------
0x-5y = -25
-5y=-25
y=5
Substituting y’s value is Equation 1
-4x+7(5)=-5
-4x+35=-5
-4x=-40
Cancellation of negative sign on both sides
x=40/4
x=10
[x,y]=[10,5]
The answer to this one is W=-3/5 I think
