Use the distributive property.
3(6 + x) = 24
18 + 3x = 24
3x = 6
x = 2
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Answer: True</h3>
The key word here is "may" meaning that we could easily have 3 rational roots as well. An example of a cubic having 3 irrational roots would be
(x-1)(x-2)(x-3) = x³ - 6x² + 11x - 6
This has the rational roots x = 1, x = 2, x = 3.
However, we could easily replace 1,2,3 with any irrational numbers we want. So that's why the statement "a cubic has three irrational roots" is sometimes true.
In some cases, a cubic may only have 1 real root and the other 2 roots are imaginary.
1. (0,1) , (1,6) , (2,11)
2. (0,10) , (1,9) , (2,8)
3. (0,0) , (1,2) , (2,4)
hope this helps.
Answer: No
Step-by-step explanation:
I took a test and this answer was correct.
Let X= the number of tickets sold at $35 each
Let 350 -X = the number of tickets sold at $25 each
The number of tickets sold for each type will be computed as follows:
X(35)+(350-X)25=10250
35X+8750-25X=10250
10X=10250-8750
X=1500/10
X=150 the number of tickets sold at $35 each
350-150 the number of tickets sold at $25 each
To recheck:
150(35)+200(25)
5250+5000
10250
