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ANEK [815]
3 years ago
6

Can someone help me with this?

Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

Solution given:

<J=90°[tangent to the circle is perpendicular to radius]

In right angled triangle ∆KJL

base[b]=11

hypotenuse [h]=11+7=18

perpendicular [p]=x

by using Pythagoras law

p²+b²=h²

x²+11²=18²

x²=18²-11²

x=√203

x=14.25

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The path of a projectile launched from a 26-ft-tall tower is modeled by the equation y = −16t2 + 64t + 26. What is the maximum h
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Answer:

The maximum height of the projectile is 90 ft

Step-by-step explanation:

Here, we want to get the maximum height reached by the projectile

The answer here will be the y-coordinate value of the vertex form of the given equation

so firstly, we have to write the equation in the vertex form

We have this as;

y = -16t^2 + 64t + 26

That will be;

y = a(x-h)^2 + k

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where the vertex of the equation is;

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2 Points
sasho [114]

Answer:

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4 years ago
What are the factors of 14 and the prime number
Dafna11 [192]
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