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ANEK [815]
3 years ago
6

Can someone help me with this?

Mathematics
1 answer:
rewona [7]3 years ago
8 0

Answer:

Solution given:

<J=90°[tangent to the circle is perpendicular to radius]

In right angled triangle ∆KJL

base[b]=11

hypotenuse [h]=11+7=18

perpendicular [p]=x

by using Pythagoras law

p²+b²=h²

x²+11²=18²

x²=18²-11²

x=√203

x=14.25

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3 years ago
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luda_lava [24]

Answer:

<h3>hello there!</h3>

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6 0
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