Someone pls help me look at the picture

Construct a 99% confidence interval for the population mean, mu. Assume the population has a normal distribution. A group of 1

Zarrin [17]

Answer:

99% confidence interval for the population mean is [19.891 , 24.909].

Step-by-step explanation:

We are given that a group of 19 randomly selected students has a mean age of 22.4 years with a standard deviation of 3.8 years.

Assuming the population has a normal distribution.

Firstly, the pivotal quantity for 99% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean age of selected students = 22.4 years

s = sample standard deviation = 3.8 years

n = sample of students = 19

$\mu$ = population mean

<em>Here for constructing 99% confidence interval we have used t statistics because we don't know about population standard deviation.</em>

So, 99% confidence interval for the population mean, $\mu$ is ;

P(-2.878 < $t_1_8$ < 2.878) = 0.99 {As the critical value of t at 18 degree of

freedom are -2.878 & 2.878 with P = 0.5%}

P(-2.878 < $\frac{\bar X - \mu}{\frac{s}{\sqrt{n} } }$ < 2.878) = 0.99

P( $-2.878 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X - \mu}$ < $2.878 \times {\frac{s}{\sqrt{n} } }$ ) = 0.99

P( $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ < $\mu$ < $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ) = 0.99

<u>99% confidence interval for</u> $\mu$ = [ $\bar X -2.878 \times {\frac{s}{\sqrt{n} }$ , $\bar X +2.878 \times {\frac{s}{\sqrt{n} }$ ]

= [ $22.4 -2.878 \times {\frac{3.8}{\sqrt{19} }$ , $22.4 +2.878 \times {\frac{3.8}{\sqrt{19} }$ ]

= [19.891 , 24.909]

Therefore, 99% confidence interval for the population mean is [19.891 , 24.909].

6 0

3 years ago

100y−39,000=55(x−800)

hoa [83]

Answer:

y = 11/20x -50

Step-by-step explanation:

100y−39,000=55(x−800)

Distribute

100y−39,000=55x−44000

Add 39000 to each side

100y−39,000+39000=55x−44000+39000

100y = 55x -5000

Divide each side by 100

100y/100 = 55x/100 - 5000/100

y = 11/20x -50

This is slope intercept form

where 11/20 is the slope and -50 is the y intercept

4 0

2 years ago

Can someone please help me

xenn [34]

Answer:

install socratic that give u all math questions

5 0

3 years ago

Read 2 more answers

What is the image point of (1,-1)(1,−1) after a translation left 4 units and down 5 units?

DENIUS [597]

Answer:

The new point would be (-3,-6)

Step-by-step explanation:

To solve this it is nice to graph the first point at (1,-1). Then move the point left 4 units, making x -3. and then 5 units down, which would make y -6.

8 0

3 years ago

Find the mean, median, mode, and range of the data set.

kompoz [17]

Answer:

mean 11.14

Median 10

mode 10.

Explanation

Mean is sum of data divide by number of data.

Mode is the most appearing number.

3 0

2 years ago