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k0ka [10]
3 years ago
11

Help please URGRENTTTTT

Mathematics
1 answer:
lianna [129]3 years ago
8 0

Answer:

<h3>Part A</h3>

The x-intercepts are reflecting zero-profit: (0, 0) and (6, 0).

The maximum value of the graph is at vertex (3, 120): maximum profit when the price is $3.

The function is increasing until the vertex, between x-value of 0 to 3 and is decreasing once it reached the vertex, between x-value of 3 to 6.

In the first interval the sale and profit increases, in the second interval the sale and profit decreases.

<h3>Part B</h3>

<u>Average rate of change from x = 3 to x = 5 is:</u>

  • (f(5) - f(3))/(5 - 3) =
  • (60 - 120)/2 = -30

This represents the profit drop of $30 per $1 price increase when price changes from $3 to $5.

<h3>Part C</h3>
  • The domain is representing the price. It should be profitable so it is between $0 and $6.
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16y⁴ = (2y)⁴

x⁴ - 16y⁴ = x⁴ - (2y)⁴

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              = (x² + (2y)² ) (x² - (2y)² )  

               = (x² + 4y²) (x² - 4y²)

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GuDViN [60]
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You are standing 400ft away from a building that is 850ft tall. Find the angle of elevation from where you’re standing to the to
klio [65]

Answer:

The angle of elevation is approximately 64.8^o

Step-by-step explanation:

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Then the angle \theta that we are trying to find (the angle of elevation) can be found by using the arc-tangent function:

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PLZZZZ HELP <br> A. 178.3<br> B. 196.5 <br> C. 250.8<br> D. 292.5<br> E. 297. 1
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Answer:

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Step-by-step explanation:

First, find the area of the triangle using the formula a= (bh) / 2

Base x height would be 16 x 12, which is 192

192 / 2 is 96 sq meters

Then, find the area of the circle using the formula a= Pi (r^2)

If the diameter is 16, the radius would be 8 because you divide by 2

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3 years ago
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Amanda [17]

Answer:

Answer: <u> </u><u>y</u><u> </u><u>=</u><u> </u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u> </u>

Step-by-step explanation:

{ \tt{y =  - 3x + 5}}

» At point of intersection:

{ \tt{2 =  - 3x + 5}} \\ { \tt{ - 3x =  - 3}} \\ { \tt{x = 1}}

» Point of intersection is (1, 2)

• General equation of a line:

{ \tt{y = mx + c}}

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» Consider point (1, 2);

{ \tt{2 = (1 \times 1) + c}} \\ { \tt{c = 2 - 1}} \\ { \tt{c = 1}}

Equation:

{ \tt{y = x + 1}}

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2 years ago
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