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kotykmax [81]
3 years ago
10

On sports day at Lakewood middle school, gold, silver, and bronze medals were awarded to the top three finishers in each event M

iniature replicas of the medals were sold as souvenirs in booths around the field. For $26, attendees could purchase a package containing 5 gold, 4 silver, and 2 bronze replicas, or one containing 4 gold, 4 silver, and 4 bronze replicas, or one that had 3 gold, 4 silver, and 6 bronze replicas. Which system of equations may be used to find the price, in dollars, of each type of replica?
Mathematics
1 answer:
8090 [49]3 years ago
8 0

Answer:

5G + 4S + 2B = 26

2G + 2S + 2B = 13

3G + 4S + 6B = 26

Step-by-step explanation:

Given

Represent Gold with G, Silver with S and Bronze with B

Required

Determine the system of equations

The packages are represented as:

The first: 5G + 4S + 2B

The second: 4G + 4S + 4B

The third: 3G + 4S + 6B

Each of the package costs $26.

So, we have:

5G + 4S + 2B = 26 -- (1)

4G + 4S + 4B = 26 -- (2)

3G + 4S + 6B = 26 -- (3)

Divide both sides of (2) by 2

4G + 4S + 4B = 26

2G + 2S + 2B = 13

So, the system of equations are:

5G + 4S + 2B = 26

2G + 2S + 2B = 13

3G + 4S + 6B = 26

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Answer:

3. 2

4. f(n) = 3 + 4(n - 1)

Step-by-step explanation:

3. The general term of the arithmetic sequence is given by:

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To find the ninth term of this arithmetic sequence, just put $ n = 9 $ in the general term.

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In Option A, f(n) = 4 + 3(n - 1). Substitute n = 1.

We get f(1) = 4 + 3(0) = 4. This is not the first term in the sequence and can be eliminated.

In Option B, f(n) = 4 + 3n. Substitute n = 1.

We get f(1) = 4 + 3(1) = 7, not 3 so can be eliminated.

Similarly in Option C, we get 7 and could be eliminated.

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We get f(1) = 3 + 4(1 - 1) = 3, which is the first term in the sequence.

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Answer:

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