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3 years ago

A triangle has side lengths of 6, 8, and 10. Is it a right triangle?

Mathematics

2 answers:

Katarina [22]3 years ago

6 0

Answer: Yes

Step-by-step explanation:

You can tell that two of the numbers are only 2 apart, hence CB and CA, and the other one, AB, or the bottom side, is way less.

Ilya [14]3 years ago

5 0

Answer:

YES IT IS

Step-by-step explanation:

For a triangle to be a right triangle, it must follow pythagorean theorem to find the hypotenuse (long side of triangle).

A squared + B squared = C squared

6 squared + 8 squared = 100

Since we squared our addends, we must find the square root of 100 (which is 10)

Since 10 is one of the side lengths for the hypotenuse since it is the longest, and we got 10 from pythagorean theorem, we know it is a right triangle.

Hope this helps you. Have a great rest of your day.

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Find the value of y if B is between A and C, AB is 2y, BC is 6y, and AC is 48.

Len [333]

Answer:

7. C. 6

8. H. √34

9. A. (1, 3.5)

10. J. 10

Step-by-step explanation:

7. AB = 2y, BC = 6y, AC = 48

AB + BC = AC (segment addition theorem)

Substitute the above values into the equation

2y + 6y = 48

Solve for y

8y = 48

Divide both sides by 8

8y/8 = 48/8

y = 6

8. Distance between P(2, 8) and Q(5, 3):

$PQ = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$P(2, 8) = (x_1, y_1)$

$Q(5, 3) = (x_2, y_2)$

$PQ = \sqrt{(5 - 2)^2 + (3 - 8)^2}$

$PQ = \sqrt{(3)^2 + (-5)^2}$

$PQ = \sqrt{9 + 25}$

$PQ = \sqrt{34}$

9. Midpoint (M) of segment LB, for L(8, 5) and B(-6, 2) is given as:

$M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})$

Let $L(8, 5) = (x_1, y_1)$

$B(-6, 2) = (x_2, y_2)$

Thus:

$M(\frac{8 + (-6)}{2}, \frac{5 + 2}{2})$

$M(\frac{2}{2}, \frac{7}{2})$

$M(1, 3.5)$

10. M = -10, N = -20

Distance between M and N, MN = |-20 - (-10)|

= |-20 + 10| = |-10|

MN = 10

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