1.
no, there will never be a negative y-value. <span>y= |x| will always be nonnegative. |x| can be distance x is from 0 and a distance can never be negative.
</span>2.
you can define it as
y = |x| = x if x ≥ 0, -x if x < 0
absolute value can be
interpreted as a function that does not allow negative real numbers,
forcing them to be positive (leaving 0 alone). if the input x is more
than or equal 0, then x stays positive so there is no need to do
anything: "x if x ≥ 0".
if the input is less than 0, then it is an
negative number and needs a negative coefficient to negate the negative:
"-x if x < 0"
example: if x = -3, then it will take the "-x if x < 0" piece resulting in y = -(-3) = 3, which is what |-3| does
if x = 1, it will take the "x if x ≥ 0" piece and just have y = 1 which is what |1| does.
for x = 0, it will take the "x if x ≥ 0" and just have y = 0 which is what |0| does
Answer:
cool....
Step-by-step explanation:
Answer: The missing number is 55
The denominators are 20 and 100. We multiply by 5 to jump from the smaller denominator to the larger.
Do the same for the numerators
11*5 = 55
Or you can solve the proportion below for x
11/20 = x/100
11*100 = 20*x
1100 = 20x
20x = 1100
x = 1100/20
x = 55
Answer: 
Step-by-step explanation:
multiply the numberator and denominator:
3*-1 = -3
and
4*4 = 16 so,
is the answer
