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2 years ago

Solve this exercise using the fact that the sum of the measures of the three angles of a triangle is 180.

Mathematics

1 answer:

den301095 [7]2 years ago

7 0

Answer:

X=70

Step-by-step explanation:

70 + 75 + 35 =180

x + x+5 + x-35

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Find the y- intercept of the following equation y = 6x + 10<br> Please help quick!

n200080 [17]

The slope is 6 and the y intercept is 10. Mark brainliest would be aporeciated

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2 years ago

Describe and correct any error a student may have made when solving the equation

Lady_Fox [76]

Answer:

The student made an error during the distributive property in the second step where they multiplied 0.15 by -0.2 to equal -0.3 when it should have been -0.03.

Step-by-step explanation:

$0.15(y-0.2)=2-0.5(1-y)\\0.15y-0.03=2-0.5+0.5y\\0.15y-0.03=1.5+0.5y\\100(0.15y-0.03)=100(1.5+0.5y)\\15y-3=150+50y\\15y-3-15y-150=150+50y-15y-150\\-153=35y\\-\frac{153}{35}=y$

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2 years ago

Zach wants to have a flower bed in his backyard he measures the area of the flower bed to be 10 square feet the actual measureme

MrRissso [65]

The answer would be- 6%

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2 years ago

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

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2 years ago

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Zigmanuir [339]

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