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Greeley [361]
3 years ago
13

*picture from last questions!!*

Mathematics
1 answer:
deff fn [24]3 years ago
5 0
1. Exponential Function
2. Quadratic Function
3. Piecewise Function
4. Absolute Value Function
5. Is choice 4
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I’LL GIVE YA BRAINLESS!! I need the answer ASAP
Lady_Fox [76]

Answer: The answers are 20% and 40%

Step-by-step explanation:

Cost price is $240,000

The percentage of $48000 will be

(48000/240000) × 100

= 20%

The percentage of $96000 will be

(96000/240000) ×100

= 40%

4 0
3 years ago
HELP ASAP:<br> What is the value of x?<br> Enter your answer in the box.
Bess [88]

Answer: x=21

Step-by-step explanation: 100+x-4+3x=180

4x=84

x=21

4 0
4 years ago
Lines m and n are parallel. The measure of angle 6 is 55 114 57.6 3 What is the measure of angle 1? 1552​
Alex Ar [27]

Answer:

125 degree

Step-by-step explanation:

As m // n, so angle 2 and angle 6 is the same so angle 2 = 55 degree, then angle 1 + angle 2 = 180 degree, so angle 1 = 180 - 55 = 125 degree.

If it is helpful, please give me Brainliest.

5 0
4 years ago
How do I write 0.5 million dollars as a decimal...for example, 1.0 million is 1,000,000. I don't get we're you put the decimal p
Lana71 [14]
Well .5 of a million dollars is 500,000. so you are right the decimal of 500,000 is .5 million.
6 0
3 years ago
Derivatives concept:<br> Exercises using the definition of derivatives:<br><br> (Full development)
krok68 [10]

(A) <em>f(x)</em> = 7 is constant, so <em>f(x</em> + <em>h)</em> = 7, too, which makes <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 0. So <em>f'(x)</em> = 0.

(B) <em>f(x)</em> = 5<em>x</em> + 1   ==>   <em>f(x</em> + <em>h)</em> = 5 (<em>x</em> + <em>h</em>) + 1 = 5<em>x</em> + 5<em>h</em> + 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 5<em>h</em>

Then

\displaystyle f'(x) = \lim_{h\to0}\frac{5h}h = \lim_{h\to0}5 = 5

(C) <em>f(x)</em> = <em>x</em> ² + 3   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 3 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 3

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ²

\implies\displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2}h = \lim_{h\to0}(2x+h) = 2x

(D) <em>f(x)</em> = <em>x</em> ² +<em> </em>4<em>x</em> - 1   ==>   <em>f(x</em> + <em>h)</em> = (<em>x</em> + <em>h</em>)² + 4 (<em>x</em> + <em>h</em>) - 1 = <em>x</em> ² + 2<em>xh</em> + <em>h</em> ² + 4<em>x</em> + 4<em>h</em> - 1

==>   <em>f(x</em> + <em>h)</em> - <em>f(x)</em> = 2<em>xh</em> + <em>h</em> ² + 4<em>h</em>

\implies \displaystyle f'(x) = \lim_{h\to0}\frac{2xh+h^2+4h}h = \lim_{h\to0}(2x+h+4) = 2x+4

5 0
3 years ago
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