Slope of a line passing through a point is given by: y - y1 = m(x - x1); where (x1, y1) = (2, -3) and m = 5/8.
Therefore equation of the line is y - (-3) = 5/8(x - 2)
8(y + 3) = 5x - 10
8y + 24 = 5x - 10
8y - 5x = -10 - 24 = -34
5x - 8y = 34
Remember that the vertex form of a parabola or quadratic equation is:
y=a(x-h)^2+k, where (h,k) is the "vertex" which is the maximum or minimum point of the parabola (and a is half the acceleration of the of the function, but that is maybe too much :P)
In this case we are given that the vertex is (1,1) so we have:
y=a(x-1)^2+1, and then we are told that there is a point (0,-3) so we can say:
-3=a(0-1)^2+1
-3=a+1
-4=a so our complete equation in vertex form is:
y=-4(x-1)^2+1
Now you wish to know where the x-intercepts are. x-intercepts are when the graph touches the x-axis, ie, when y=0 so
0=-4(x-1)^2+1 add 4(x-1)^2 to both sides
4(x-1)^2=1 divide both sides by 4
(x-1)^2=1/4 take the square root of both sides
x-1=±√(1/4) which is equal to
x-1=±1/2 add 1 to both sides
x=1±1/2
So x=0.5 and 1.5, thus the x-intercept points are:
(0.5, 0) and (1.5, 0) or if you like fractions:
(1/2, 0) and (3/2, 0) :P
17 = -13 - 8x .....add 13 to both sides
13 + 17 = -8x
30 = -8x...now divide both sides by -8
-30/8 = x...reduce
- 15/4 or -3 3/4 = x <===
2 - 3 (2x - 5) = 6x + 1
2 -6x +15 = 6x +1 distribute the -3 to (2x -5)
-6x + 17 = 6x + 1 add 2 + 15
16 = 12x add the -6x to the positive 6x and subtract the 1 from 17
1 1/3 = x divide 16/12
