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2 years ago

Let E= {prime numbers less than 30} Work out n(E)

Mathematics

2 answers:

Doss [256]2 years ago

4 0

Answer:

Step-by-step explanation:

E={2,3,5,7, 11, 13, 17, 19, 23, 29}

therefore,

n(E)={10}

sleet_krkn [62]2 years ago

4 0

Answer:

10 if I recall correctly

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Answer:

65.75% change

Step-by-step explanation:

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3 years ago

Expand log_1/2(3x^2/2) using the properties and rules for logarithms. Please help.

Naily [24]

Answer:

$\frac{0.1761+2\log(x)}{-0.3010}$

Step-by-step explanation:

Data provided:

$\log_{1/2}(\frac{3x^2}{2})$

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) $\log(\frac{A}{B})$ = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3x^2)$ - $\log_{1/2}(2)$

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+\log_{\frac{1}{2}}(x^2)$ - $\log_{1/2}(2)$

using property 3

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+2\log_{\frac{1}{2}}(x)$ - $\log_{1/2}(2)$

also,

$\log_a(x)=\frac{\log(x)}{\log(a)}$

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}$

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.4771+2\log(x)-0.3010}{0-0.3010}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.1761+2\log(x)}{-0.3010}$

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3 years ago

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What is the value of the rational expression 2x-1/x+5 when x = 0?

Reptile [31]

2x-1/x+5

2(0) - 1
= ---------------
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 - 1
= ----------
5

answer
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