<span><u>Answer</u>
25c^2-4/9
<u>Explanation</u>
In this question you are expected to expand (5c+2/3)(5c-2/3)
(5c+2/3)(5c-2/3)=(5c×5c)-(5c×2/3)+(5c×2/3)-(2/3×2/3)
=25c^2-10c/3+10c/3-4/9
25c^2-4/9
The expanded form of (5c+2/3)(5c-2/3) is 25c^2-4/9 and this is what the question requires of you to do.</span>
To solve this question, you can break it into 2 parts. First evaluate the function g(X)=9x+9 for g(-6). Which is g(-6) = 9(-6)+9 = -45. Then evaluate f(-45). F(-45)= 4(-45)+6= -180+6= -174. The final answer for f(g(-6))= -174.
Answer:
Explanation:
The function that represents the number of E.coli bacteria cells per 100 mL of water as the time t years elapses is:
The base, 1.123, represents the multiplicative constant rate of change of the function, so you just must substitute 1 for t in the power part of the function:
Then, the multiplicative rate of change is 1.590, which means that every year the number of E.coli bacteria cells per 100 mL of water increases by a factor of 1.590, and that is 1.59 - 1 = 0.590 or 59% increase.
Answer:
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Answer:
120
Step-by-step explanation: