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kykrilka [37]
3 years ago
13

The LCM of two numbers is 48. The number one in the ratio 2:3. Then Sum of the numbers is:

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
6 0

Answer:

40

Step-by-step explanation:

Let the numbers be 2x and 3x

Then their L.C.M. = 6x

BUT also their LCM=48

6x=48

x=48/6

x=8

So,

First number=2x=2x8=16

Second number=3x=3x8=24

The numbers are 16 and 24.

Hence required sum =(16+24)=40

So none of the options are correct

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Answer:

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Step-by-step explanation:

Simplifying

3x + -7y = 11

Solving

3x + -7y = 11

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '7y' to each side of the equation.

3x + -7y + 7y = 11 + 7y

Combine like terms: -7y + 7y = 0

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Divide each side by '3'.

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Step-by-step explanation:

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dsp73

Answer:

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Step-by-step explanation:

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cosine = adjacent (to angle)/hypotenuse

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