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3 years ago

Which equation has only one solution (Algebra ll) URGENT

Mathematics

1 answer:

Yanka [14]3 years ago

5 0

option C

I hope it will help you

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lina2011 [118]

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3 years ago

Plotting points in the four quadrants

galben [10]

Answer:

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3 years ago

A bag contains 37 coins consisting of only dimes and quarters. The total amount of money in the bag is $6.85. How many dimes are

bogdanovich [222]

I think it’s 30.15 or 43.85 if nether I’m dumb

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3 years ago

Read 2 more answers

4x + 2(x - 5) - 3(2x -4)

Olegator [25]

Answer:

Step-by-step explanation:

Pull out like factors :

2x - 4 = 2 • (x - 2)

(4x + (2 • (x - 5))) - 6 • (x - 2)

(4x + 2 • (x - 5)) - 6 • (x - 2)

Final Answer:

5 0

4 years ago

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. If the denominator of the or

Alchen [17]

Answer:

$\dfrac{7}{6}$

Step-by-step explanation:

Let $\dfrac{a}{b}$ be the original fraction.

If the numerator of a fraction is increased by six, the value of the fraction will increase by one. Hence,

$\dfrac{a+6}{b}=\dfrac{a}{b}+1$

If the denominator of the original fraction is increased by 36, the value of the original fraction will decrease by one. Hence,

$\dfrac{a}{b+36}=\dfrac{a}{b}-1$

Add these two equalities:

$\dfrac{a+6}{b}+\dfrac{a}{b+36}=\dfrac{a}{b}+1+\dfrac{a}{b}-1\\ \\\dfrac{a+6}{b}+\dfrac{a}{b+36}=2\dfrac{a}{b}\\ \\\dfrac{a}{b+36}=\dfrac{2a-(a+6)}{b}\\ \\\dfrac{a}{b+36}=\dfrac{a-6}{b}\\ \\ab=(a-6)(b+36)\\ \\ab=ab+36a-6b-216\\ \\36a-6b-216=0\\ \\6a-b-36=0\\ \\b=6a-36$

Substitute it into the first equation:

$\dfrac{a+6}{6a-36}=\dfrac{a}{6a-36}+1\\ \\\dfrac{a+6}{6(a-6)}=\dfrac{a}{6(a-6)}+1\\ \\a+6=a+6(a-6)\\ \\a+6=a+6a-36\\ \\6a=6+36\\ \\6a=42\\ \\a=7\\ \\b=6\cdot 7-36=42-36=6$

Thus, the initial fraction was

$\dfrac{7}{6}$

6 0

4 years ago

Which equation has only one solution (Algebra ll) *URGENT*

Which equation has only one solution (Algebra ll) URGENT