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Lemur [1.5K]
4 years ago
6

The total cost for a dinner reception, , is a function of the number of people, , attending the event. The equation, , can be us

ed to represent this situation. The catering company requires a minimum of 20 guests. Which inequalities represent the domain & range of this problem?
Mathematics
1 answer:
olya-2409 [2.1K]4 years ago
5 0

Answer:

1,800= 45 x ( x is the amount of weeks)

Step-by-step explanation:

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50% of all the cakes jenny baked that week were party cakes,1/5 were fruit cakes, and the remainder were sponge cakes. what perc
irina1246 [14]

Answer:

30%

Step-by-step explanation:

1/5 = 20%

so, 50 - 20 = 30

7 0
4 years ago
What is tan(B)?<br> B<br> 5<br> 13<br> 5<br> 12<br> ?<br> tan(B) =<br> =<br> Enter
SOVA2 [1]

Answer:

tan B = 12/5

Step-by-step explanation:

Since this is a right  triangle, we can use trig functions

tan theta = opp side/ adj side

tan B = 12/5

3 0
3 years ago
The sum of the two numbers is 42. The smaller number is 63 less than twice the larger number. Find both numbers.
Lisa [10]
STEP 1:
identify variables and equations

x= larger number
y= smaller number

FIRST EQUATION
x + y= 42

SECOND EQUATION
y= 2x - 63


STEP 2:
substitute the y value in second equation in for y in first equation

x + y= 42
substitute y value from 2nd equation

x + (2x - 63)= 42
combine like terms

3x - 63= 42
add 63 to both sides

3x= 105
divide both sides by 3

x= 35 larger number


STEP 3:
find y value; substitute step 2 x value into either original equation

x + y= 42

35 + y= 42
subtract 35 from both sides

y= 7 smaller number


ANSWER: larger number is x= 35; smaller number is y= 7.

Hope this helps! :)
4 0
3 years ago
Help ASAP) What is the volume of the rectangular prism? Type the answer in the boxes below. Will Mark Brainliest and look at the
Mashutka [201]
V=30

V= WxHxL

V= 2x3x5

V=6x5

V=30cm3
8 0
3 years ago
Write a proportion that could be used to solve for each variable.
Ivahew [28]

Answer:

6 buttons per package

Step-by-step explanation:

6 x 4=24

4 0
3 years ago
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