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allsm [11]
3 years ago
8

PLZZZZ HELP ME PLZZZZZZZ

Mathematics
2 answers:
myrzilka [38]3 years ago
5 0
-2x + 16 = x + 28
-12 = 3x
X = -4
forsale [732]3 years ago
5 0
1) expand

-2+16=x+28

2) add 2x to both sides

16=x+28+2x

3) simplify x+28+2x to 3x+28

16=3x+28

4) subtract 28 from both sides

16-28=3x

5) simplify 16-28 to -12

-12=3x

6) divide both sides by 3

-12/3=x

7) simplify 12/3 to 4

-4=x

8) switch sides

x=-4
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A positive real number is 1 more than another. When -2 times the smaller is added to the square of the larger, the result is 33.
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Answer:

The smaller number is 4√2 and the larger number is (4√2 + 1).

Step-by-step explanation:

Let the two numbers be <em>x </em>and <em>y</em>, where <em>y</em> is the larger of the two numbers.

Since <em>y</em> is the larger number, it is one more than the smaller number. So:

y=x+1

When negative two times the smaller is added to the square of the larger, the result is 33. In other words:

-2x+y^2=33

Substitute:

-2x+(x+1)^2=33

Solve for <em>x</em>. Square:

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Simplify:

x^2+1=33

Subtract one from both sides:

x^2=32

And take the square root of both sides:

x=\pm\sqrt{32}=\pm 4\sqrt{2}

Since <em>y</em> is positive, we can ignore the negative case. So, the smaller number is:

x=4\sqrt{2}\approx5.66

And the larger number is:

y = 4\sqrt{2} + 1 \approx6.66

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