Question

Fine the equation of the line that is perpendicular to the given line and passes through the given point. Enter the right side of the equation as a single fraction. y=7x-1/4;(5,5)
The equation is y=
Please help it’s urgent! :)

Answer 1

Answer:

$y=-\frac{4}{7} x+\frac{55}{7}$

Step-by-step explanation:

Change the given equation to slope-intercept to get $y=\frac{7}{4}x-\frac{1}{4}$. When you multiply the slopes of perpendicular lines, you get -1. -1 divided by $\frac{7}{4}$ is $-\frac{4}{7}$. The slope of the new line is then $-\frac{4}{7}$. The perpendicular line passes through (5, 5) so you can have the equation$5=-\frac{4}{7} (5)+b$. Simplifying gets $b = \frac{55}{7}$ . So now the final equation for the perpendicular line is $y=-\frac{4}{7} x+\frac{55}{7}$