For the first question, divide 200 by the seconds. You would get the answer 9.07. This answer is rounded to the nearest hundredth.
The second question, you would convert that to feet by using the units 1 meter = 3.28084.
If you converted it, the answer woudl be 29.75722 ft/second
If there is a 60% chance there are female, then that must mean that 40% of the teachers are male.
If 40% of all the teachers is 36, then 20% of all the teachers are 18 in number
So, when we multiply 20% by 5 (to get 100% = all the teachers), we get:
18 x 5 = 90 teachers in total
Hope I helped xx
The coordinates of the center of this circle will be the average between the extreme points
C = ( (xo+x1)/2 , (yo+y1)/2)
Where,
xo = 3 and x1 = 9
yo = 8 and y1 = 16
Then us stay with"
C = ( (3+9)/2 , (8+16)/2)
C = ( 12/2 , 24/2)
C = ( 6 , 12 )
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
The domain would have to be greater than or equal to 0, assuming x is the number of people attending. You can't have a negative number of people!
