All categories

3 years ago

Find the solution(s) for x in the equation below. x^2 - 25 = 0

Mathematics

1 answer:

Zepler [3.9K]3 years ago

5 0

Answer: x = 5

Step-by-step explanation:

x^2 - 25 = 0

x^2 = 25

x = √25

x = 5

You might be interested in

What is the image point of (3, 7) after a translation right 5 units and up 1 unit?

navik [9.2K]

I don't actually know, im not smart, I'm just answering for the points

3 0

3 years ago

Read 2 more answers

What is the difference between a hexagon and an octagon

ki77a [65]

a hexagon has 6 sides An octagon has 8 sides.

Hope i helped <3

5 0

4 years ago

Read 2 more answers

HELP IM BEGGING YOU !

stepan [7]

Answer:

if sam paid 500$ that would mean he would be a gym member for 20 months.

6 0

3 years ago

Read 2 more answers

These are 3 questions btw so i need 3 answers!

monitta

Answer:

y = - $\frac{7}{2}$ cos ( $\frac{1}{2}$ x ) , y = cos ( 3x ) + 2

Step-by-step explanation:

Image 1.

The graph is reflection of cosine over x-axis and max is 3.5 ⇒ A = - $\frac{7}{2}$

Period is ( 4 π ) ⇒ B = $\frac{1}{2}$

There are no horizontal and vertical shifts ⇒ C = D = 0

y = -  $\frac{7}{2}$  cos (  $\frac{1}{2}$  x )

Image 3.

The graph of cosine shifted 2 units up only ⇒ D = 2 , C = 0

Period of the given function is $\frac{2\pi }{3}$ ⇒ B = 3

y = cos ( 3x ) + 2

6 0

3 years ago

You bike 1 mile the first day of your training, 1.3 miles the second day, 1.9 miles the third day, and 3.1 miles the fourth d

JulsSmile [24]

Answer:

19.9 miles

Step-by-step explanation:

In this problem we have:

$d_1=1 mi$ is the distance travelled during the 1st day

$d_2=1.3 mi$ is the distance travelled during the 2nd day

$d_3=1.9 mi$ is the distance travelled during the 3rd day

$d_4=3.1 mi$ is the distance travelled during the 4th day

We notice that the difference between the distance travelled on the (n+1)-th day and the distance travelled on the n-th day doubles every day. In fact:

$d_2-d_1=0.3\\d_3-d_2=2\cdot 0.3 = 0.6\\d_4-d_3=2\cdot 0.6 = 1.2$

Which can be rewritten using the general formula:

$d_{n+1}-d_n=2(d_n-d_{n-1})$

This means that

$d_{n+1}=d_n+2(d_n-d_{n-1})$

By applying this formula recursively, we can find the 7th term, which is the distance travelled on the 7th day:

$d_1=1\\d_2=1.3\\d_3=1.9\\d_4=3.1\\d_5=3.1+2\cdot 1.2=5.5\\d_6=5.5+2\cdot 2.4=10.3\\d_7=10.3+2\cdot 4.8=19.9 mi$

So, the distance travelled on the 7th day is 19.9 miles.

7 0

4 years ago