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Serggg [28]
3 years ago
7

How would you turn it into a table?

Mathematics
2 answers:
kari74 [83]3 years ago
6 0
Answer: do what now??
Ivan3 years ago
5 0

Step-by-step explanation:

turn what i.to a table ??

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What is the value of the expression<br> below when x = 10?<br> 4x + 5<br> 8r +5
GarryVolchara [31]
There no solution sorry man
8 0
3 years ago
Which one would it be?
Leni [432]
C is the answer.
in the original function, when x=0, y=-1
in the new function, to make y=-1, x+3=0, x=-3. From the original 0 to -3 is a shift of 3 units to the left. 
6 0
3 years ago
Simplify 4(6 - 2x) - 3(3 - 4x)
laiz [17]
4x+15
hope this helped!
6 0
3 years ago
Read 2 more answers
A,B and C are the vertices of one triangle.
dsp73

Answer:


Step-by-step explanation:

Given: The triangle with coordinate A(4,6), B(2,-2) and C(-2,-4). D is the mid point of AB and E is the mid point of AC.

To prove: DE is parallel to BC.

Construction: Join DE.

Proof: If we prove the basic proportionality theorem that is \frac{AD}{DB}=\frac{AE}{EC}, then it proves that DE is parallel to BC.

Now, Mid Point D has coordinates=(\frac{4+2}{2},\frac{6-2}{2})=(3,2) and Mid Point E has coordinates=(\frac{4-2}{2},\frac{6-4}{2})=(1,1)

Now, AD= \sqrt{(4-3)^{2}+(6-2)^{2}}=\sqrt{17}

DB=\sqrt{(3-2)^{2}+(2+2)^{2}}=\sqrt{17}

AE=\sqrt{(4-1)^{2}+(6-1)^{2}}=\sqrt{34}

EC=\sqrt{(1+2)^{2}+(1+4)^{2}}=\sqrt{34}

Now, \frac{AD}{DB}=\frac{AE}{EC}

=\frac{\sqrt{17}}{\sqrt{17}}=\frac{\sqrt{34}}{\sqrt{34}}=\frac{1}{1}

Hence, \frac{AD}{DB}=\frac{AE}{EC}

Thus, By basic proportionality theorem, DE is parallel to BC.

4 0
3 years ago
Read 2 more answers
F(x) = x 2 + 1, find f(a + 1)
Ray Of Light [21]
<span>f(x) = x^2 + 1, find f(a + 1)
so
</span> f(a + 1) = (a+1)^2 +1
 f(a + 1) = a^2 + 2a + 1 + 1
 f(a + 1) = a^2 + 2a + 2
3 0
3 years ago
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