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nekit [7.7K]
4 years ago
9

An empty box weighs 200g The box is filled with birthday party goody bags and it now weighs 6.2kg Each goody bag weighs 150g Wor

k out how many goody bags are inside the boz
Mathematics
1 answer:
leva [86]4 years ago
5 0

Answer:

The answer to your question is: 40 bags

Step-by-step explanation:

Data:

box weight = 200 g

Box weight + bags = 6.2 kg

1 bad weight = 150 g

Process:

We need to know the weight of all the bags so we subtract the box weight from the total weight

Goody bags weight = 6200 g - 200 g

Goody bags weight = 6000 g

To find the weight of one bag we use a rule of three

            1 goody bags ----------------   150 g

                      x           ----------------    6000 g

x =  (6000) (1) / 150 = 40 bags

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Answer:

(x,y,z)=(1477, 1464, 1437)

Step-by-step explanation:

Consider the selling of the units positive earning and the purchasing of the units negative earning.

<h3>Case-1:</h3>
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3x  +  5y - 4z = 6000

<h3>Case-2:</h3>
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- x    + 4y  +  6z = 13000

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\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

<u>Solving </u><u>the </u><u>system </u><u>of </u><u>equations</u><u>:</u>

we will consider elimination method to solve the system of equations. To do so ,separate the equation in two parts which yields:

\begin{cases}3x  +  5y - 4z = 6000\\2x   - 3y  +  z = 0\end{cases}\\\begin{cases}2x   - 3y  +  z = 0\\ - x    + 4y  +  6z = 13000\end{cases}

Now solve the equation accordingly:

\implies\begin{cases}11x-7y=6000\\-13x+22y=13000\end{cases}

Solving the equation for x and y yields:

\implies\begin{cases}x= \dfrac{223000}{151}\\\\y= \dfrac{221000}{151}\end{cases}

plug in the value of x and y into 2x - 3y + z = 0 and simplify to get z. hence,

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