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3 years ago

14

I need someone to save me this is so hard

1 answer:

Inga [223]3 years ago

4 0

Answer:

Oh I want the ponts give me the branlest to!

Step-by-step explanation:

You might be interested in

in a single elimination tournament starting with 128 teams, half of the remaining teams are eliminated in each round. a) make a

lesya [120]

B) no
c) D: (0, 128) domain is what are the possible numbers that can be put into a function. the reason it is 0 to 128 is because you cant have a negative number in this situation and 128 is the max because thats what you started out with
d) 4 teams

7 0

3 years ago

cathi scored 6 baskets in each of her last 3 basketball games. Each basket was worth 2 points. how many points did cathi score i

jonny [76]

Answer:

p=36

Step-by-step explanation:

3(6*2)=p

3(12)=p

36=p

Sorry if its hard to understand I'm new to anwering questions on brainly

4 0

3 years ago

Help please! <br>using quadratic formula <br>round ti nearest hundred

Lera25 [3.4K]

Answer:

x = 0.19 or x = -0.76

Step-by-step explanation:

Equation: 7²-4x = 2

reordering the equation,

7x²-4x-2 = 0

Applying,

x = [-b±√(b²-4ac)]/2a..................... Equation 1

From the question,

Given: a = 7, b = -4, c = -2

Substitute these values into equation 1

x = [-4±√(-4²-(2×7×-2)]/(2×7)

x = [-4±√(16+28)]/14

x = (-4±√44)/14

Either

x = (-4+√44)/14

x = (-4+6.63)/14

x = 2.63/14

x = 0.19

or

x = (-4-√44)/14

x = (-4-6.63)/14

x = -10.63/14

x = -0.76

3 0

3 years ago

If f(x) = 5x − 1 and g(x) = 2x2 + 1, what is the value of (f × g)(-3)?

Softa [21]

f(x) = 5x − 1 and g(x) = 2x^2 + 1

(f × g)(x) = (5x − 1)(2x^2 + 1)

(f × g)(x) = 10x^3 - 2x^2 + 5x - 1

Substitute x = - 3

(f × g)(-3) = 10(-3)^3 - 2(-3)^2 + 5(-3) - 1

(f × g)(-3) = 10(-27) - 2(9) -15 - 1

(f × g)(-3) =-270 - 18 - 16

(f × g)(-3) = -236

Answer

- 236

6 0

3 years ago

f(x) is a quadratic function with x-intercepts at (−1, 0) and (−3, 0). If the range of f(x) is [−4, [infinity]) and g(x) = 2x^2

iren2701 [21]

Answer with Step-by-step explanation:

We are given that function f(x) which is quadratic function.

x -intercept of function f(x) at (-1,0) and (-3,0)

x-Intercept of f means zeroes of f

x=-1 and x=-3

Range of f =[-4, $\infty$ )

g(x)= $2x^2+8x+6=2(x^2+4x+3)$

$g(x)=0$

$2(x^2+4x+3)=0$

$x^2+4x+3=0$

$x^2+3x+x+3=0$

$x(x+3)+1(x+3)=0$

$(x+1)(x+3)=0$

$x+1=0\implies x=-1$

$x+3=0\implies x=-3$

Therefore, x-intercept of g(x) at (-1,0) and (-3,0).

Substitute x=-2

$g(-2)=2(-2)^2+8(-2)+6=8-16+6=-2$

$g(x)=2(x^2+4x)+6$

$g(x)=2(x^2+2\times x\times 2+4-4)+6=2(x^2+2\times x\times 2+4)-8+6$

$g(x)=2(x+2)^2-2$

By comparing with the equation of parabola

$y=a(x-h)^2+k$

Where vertex=(h,k)

We get vertex of g(x)=(-2,-2)

Range of g(x)=[-2, $\infty$ )

Zeroes of f and g are same .

But range of f and g are different.

Range of f contains -3 and -4 but range of g does not contain -3 and -4.

f and g are both quadratic functions.

3 0

3 years ago