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3 years ago

10

Sabrina wanted to wrap a giftbox of length 8 inches, height 6 inches, and width 4 inches. How much wrapping paper does Sabrina n

eed to buy?

1 answer:

Lesechka [4]3 years ago

5 0

Answer:

208inches

Step-by-step explanation:

Surface Area=2x(8x6+8x4+6x4)=208 feet^2

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What is the answer to 1/4x=2?

Anvisha [2.4K]

Answer: ok :)

Explanation:

7 0

3 years ago

The answers for the tables

Alex787 [66]

Answer:

<em>Shown in Step-By-Step, written in </em><em>bold</em><em> text.</em>

Step-by-step explanation:

16) x : 1 y: -3

2 0

3 9

3x - 6

3(1) - 6 = -3

3(2) - 6 = 0

3(3) - 6 = 9

17) x: 1 y: -10

2 -12

3 -14

-2(x + 4) = -2x - 8

-2(1) - 8 = -10

-2(2) - 8 = -12

-(3) - 8 = -14

3 0

3 years ago

A notebook costs $1.25 and has a 6% tax added on. Calculate the TOTAL cost of the notebook including tax. (*Round to the nearest

Sunny_sXe [5.5K]

Answer:

$1.33

Step-by-step explanation:

To find the cost of the 6% tax, multiply the tax by the cost of the notebook.

tax = (0.06)(1.25) = $0.075

Add this tax cost to the cost of the notebook for the total.

total = 1.25 + 0.075 = $1.325 = $1.33

Round to the nearest hundreth.

OR

You could multiply:

total = (1.06)(1.25) = $1.325 = $1.33

3 0

2 years ago

Read 2 more answers

Tell whether (5, 2) is a solution of x - y < 0.

meriva

Your points: (5,2)

Your inequality: x - y < 0

Plug 5 in for x and y in for 2

5 - 2 < 0.

Simplify the left side

3 < 0.

3 is not less than 0

(5,2) is not a solution of x - y < 0

5 0

3 years ago

A volume of a coin is 113.04 mm2 what is the approximate of a sphere that has the same height and a circular base with the same

tia_tia [17]

We have been given that the volume of a cone is 113.04 cubic mm. We are asked to find the approximate volume of a sphere that has the same height and a circular base with the same diameter.

We know that volume of cone is $\frac{1}{3}\pi r^2\cdot h$ .

The height is equal to the diameter. We know that diameter is 2 times radius, so we can represent this information in an equation as:

$h=2r$

Upon substituting $h=2r$ in volume of cone, we will get:

$V=\frac{1}{3}\pi r^2\cdot 2r$

$V=\frac{2}{3}\pi r^3$

We know that volume of sphere is $V=\frac{4}{3}\pi r^3$ .

Upon comparing volume of cone with volume of sphere, we can see that volume of sphere is 2 times the volume of cone.

$V=2(\frac{2}{3}\pi r^3)$

Since $\frac{2}{3}\pi r^3=113.04$ , so volume of sphere would be:

$V=2(113.04)$

$V=226.08$

Therefore, volume of sphere would be 226.08 cubic mm.

4 0

3 years ago