Answer:
Step-by-step explanation:
Theorm-The Fundamental Theorem of Algebra: If P(x) is a polynomial of degree n ≥ 1, then P(x) = 0 has exactly n roots, including multiple and complex roots.
Let's verify that the Fundamental Theorem of Algebra holds for quadratic polynomials.
A quadratic polynomial is a second degree polynomial. According to the Fundamental Theorem of Algebra, the quadratic set = 0 has exactly two roots.
As we have seen, factoring a quadratic equation will result in one of three possible situations.
graph 1
The quadratic may have 2 distinct real roots. This graph crosses the
x-axis in two locations. These graphs may open upward or downward.
graph 2
It may appear that the quadratic has only one real root. But, it actually has one repeated root. This graph is tangent to the x-axis in one location (touching once).
graph 3
The quadratic may have two non-real complex roots called a conjugate pair. This graph will not cross or touch the x-axis, but it will have two roots.
You would do x+ (x+1)=137
2x+1=137
Subtract 1 from each side
2x=136
x=68.
Add 1 to 68, since they are consecutive integers.
The answer is 68 and 69
Answer:
P = 54 so
arc AC = 150
Step-by-step explanation:
Answer:
103°
Step-by-step explanation:
The marked angles have the same measure, so ...
14x+7 = 12x +17
2x = 10 . . . . . subtract 12x+7
x = 5 . . . . . . . divide by 2
(14x +7)° = 77°
∠CEA is supplementary to the marked angles:
∠CEA = 180° -77°
∠CEA = 103°
Answer:
29
Step-by-step explanation:
57+x=86
x=86-57
x=29
