Consider c as the cost of the widget so that our given equation is
c = 0.1w^2 + 20w
Take the derivate of the equation.
d/dt (c = 0.1w^2 + 20w)
dc/dt = 0.2w + 20
Given dc/dt = $16000 per month, the number of widgets would contain:
16000 = 0.2w + 20
-0.2w = 20 - 16000
-0.2w = -15980
w = 79900 widgets
        
             
        
        
        
Answer:
16
Step-by-step explanation:
 
        
                    
             
        
        
        
Answer:
d = 2cot(x) or d = 2/tan(x)
Step-by-step explanation:
The vertical distance from the jet to the top of the house represents the opposite side to the 'x' angle, while the horizontal distance, d, represents the adjacent side. Since we do not know the hypotenuse, the tangent and cotangent functions are the preferable choices:

Therefore, the distance 'd' can be expressed as d = 2cot(x) or d = 2/tan(x).