Question

The vertices of a triangle are A(1, –9), B(0, –3), C(–4, –5). Fine the length of each side. What type of triangle is triangle ABC.

Answer 1

Answer:

AB = √37

BC = 2√5

AC = √41

Type: SCALENE TRIANGLE

Step-by-step explanation:

Given the coordinates

A(1, –9), B(0, –3), C(–4, –5)

We are to find the length of each sides first. Using the formula for calculating the distance between two points, we will have;

For A(1, –9) and B(0, –3)

AB = √(-3+9)²+(0-1)²

AB = √6²+(-1)²

AB = √36+1

AB = √37

For coordinates B(0, –3) and C(–4, –5)

BC = √(-5+3)²+(-4-0)²

BC= √(-2)²+(-4)²

BC = √4+16

BC = √20

BC = 2√5

For coordinates  A(1, –9), C(–4, –5)

AC = √(-5+9)²+(-4-1)²

AC= √(4)²+(-5)²

AC = √16+25

AC = √41

Since the sides of the triangles are all different, hence the triangle is a SCALENE triangle