On the bottom line, the 106 and number 1 make a straight line and needs to equal 180 degrees.
This means number 1 = 180-106 = 74 degrees.
Because x and y are parallel, the top outside angle is the same as number 1.
6x +8 = 74
Subtract 8 from both sides:
6x = 66
divide both sides by 6:
x = 66 / 6
x = 11
Now you have x, replace x in the equation for 7x-2 to find that angle:
7(11) -2 = 77-2 = 75 degrees.
The three inside angles need to equal 180 degrees.
Angle 2 = 180 - 74 - 75 = 31 degrees.
Answer:
3/4 divided by 1/3
Step-by-step explanation:
it equals to 4
There are many ways to solve this. I think the easiest way for this one is to add the equations up.

The you solve that, now that y is gone. You get x=2.
Now plug in x into one of the original equations.

Finish solving, and you get y=8.
The answer is (2,8)
Answer:
The constant of variation is k = -2 ⇒ (B)
Step-by-step explanation:
The equation of the direct variation is y = k x, where
- k is the constant of variation
- The constant of variation k =

The given table has 4 points (-1, 2), (0, 0), (2, -4), (5, -10)
We can use one of the points <em>[except point (0, 0)]</em> to find the value of k
∵ (-1, 2) is a given point
∴ x = -1 and y = 2
∵ k = 
→ Substitute the values of x and y in the relation above
∴ k = 
∴ k = -2
The constant of variation is k = -2
Answer:
![y=[1]cos([\frac{2\pi }{3}]x)](https://tex.z-dn.net/?f=y%3D%5B1%5Dcos%28%5B%5Cfrac%7B2%5Cpi%20%7D%7B3%7D%5Dx%29)
Step-by-step explanation:
Looking at the graph, we can see the domain to be from (0 , 2π).
Now we have to find one period that corresponds to cos(x).
The half-period of cos(x) for this graph appears to be pi/3 and adding another pi/3 gets us 2pi/3 to be our cosine period.
b = 2pi/3
a is the same range as cos(x). Range: (0,0)
y = [a] * cos ([b]*x)
y = [1] * cos([2pi/3]x)