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sineoko [7]
3 years ago
7

Given that these triangles are similar, what is the perimeter of triangle PQR? Show your work.

Mathematics
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

24

Step-by-step explanation:

I use the Pythagoras theorem.

\sqrt{a^{2} +b^{2} } =c^{2}

4^{2}{x}6^{2} = c^{2}

16 x 36= 576

\sqrt{576} = 24

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Imagine you are given the diameter of a circle and asked to find its volume. Select the statement that describes what you should
ivanzaharov [21]

Answer:

We need to take the diameter and divide by 2 to find the radius

Step-by-step explanation:

The volume of a sphere is found by

V = 4/3 pi r^3

So we need the radius

We know the diameter

r = d/2

We need to take the diameter and divide by 2

3 0
3 years ago
What are the potential solutions to the equation 2ln(x+3)=0
skad [1K]
2\ln(x+3)=0\implies \ln(x+3)^2=0\implies e^{\ln(x+3)^2}=e^0\implies (x+3)^2=1

Expanding the left side gives

x^2+6x+9=1\implies x^2+6x+8=0\implies (x+4)(x+2)=0

which gives two solutions, x=-4 and x=-2. But if x=-4, then \ln(x+3)=\ln(-1), but this number isn't real, so x=-4 is an extraneous solution. Meanwhile if x=-2, you get \ln(-2+3)=\ln1=0, so this solution is correct.

"Potential solutions" might refer to both possibilities, but there is only one actual (real) solution.
4 0
3 years ago
Read 2 more answers
The diagram shows the cross-section of a wall of a cinema. It has to be painted. Work out the area that needs to be painted.
mestny [16]

Answer:

Area = 370 m²

Cost to paint = £105

Step-by-step explanation:

Area of the wall of a cinema hall = Area of a trapezoid (1)+ Area of a rectangle (2) + Area of a trapezoid (3)

Area of a trapezoid = \frac{1}{2}(b_1+b_2)h

where b_1 and b_2 are the parallel sides and h is the distance between these sides.

Area of trapezoid (1) = \frac{1}{2}(11+12)\times 6

                                  = 69 m²

Area of the rectangle (2) = Length × Width

                                         = 12 × 15

                                         = 180 m²

Area of the trapezoid (3) = \frac{1}{2}(12+10)\times 11

                                         = 121 m²

Now area of the wall = 69 + 180 + 121

                                   = 370 m²

One tin covers the area = 25 m²

Number of tins required to paint the wall = \frac{\text{Total area}}{\text{Area covered by one tin}}

= \frac{370}{25}

= 14.8

Therefore, number of tins to be purchased = 15

Cost to paint the complete wall = 15 × £7

                                                       = £105

8 0
3 years ago
Can someone please take the time out of their day and help me with this question
ruslelena [56]

Answer:

76, 76 104

Step-by-step explanation:

Angle 3 is vertical so it is congruent to Angle 2.

Angle 6 is corresponding, so it is congruent to Angle 2.

Angle 8 is linear to Angle 6, so they add to 180

5 0
2 years ago
Read 2 more answers
Please help me with these 4 question i will mark brainliest to correct answer please dont play around
crimeas [40]

Answer:

6, the property of addition.

Step-by-step explanation:

If you add 6 to both sides you used addition lol. Hope I helped, I'm not too good at explaining math sorry

8 0
3 years ago
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