Question

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Answer 1

Step-by-step explanation:

We know that area of Trapezium =

$\sf{\dfrac{1}{2} \times (Sum \ of \ its \ Diagonals) \times height}$

1/2 * (16+48) * 20

= 640 m²

Now, for semicircle,

1/2 * pi * r²

= 1/2 * 3.14 * 18.86 * 18.86

= 558.44 m²

Adding both,

1198.44 m² ~ 2000 m²

Hope it helps :)

Answer 2

Now we have to,

find the area of trapezium.

The formula we use,

→ 1/2 × (Sum of Diagonals) × height

Then put the values,

→ 1/2 × (16+48) × 20

→ 640 m²

Now we have to,

find the area of semi circle.

The formula we use,

→ 1/2 × π × r²

Then put the values,

→ 1/2 × 3.14 × (18.86)²

→ 1/2 × 3.14 × 18.86 × 18.86

→ 558.45 m²

Then we can add both values,

→ 640 + 558.45

→ 1198.45 m²

Therefore, 1198.45 m² is the area.