Answer:
x^3-1
Step-by-step explanation:
f(x)=g(x)-1 since was shifted down 1 unit x^3-1
f(x)=g(x)+1 would have been a shift up of 1 unit x^3+1
f(x)=g(x-1) shifted right 1 unit (x-1)^3
f(x)=g(x+1) shifted left one unit (x+1)^3
Anyways the answer is f(x)=x^3-1
Answer:
Step-by-step explanation:
The mean SAT score is
, we are going to call it \mu since it's the "true" mean
The standard deviation (we are going to call it
) is

Next they draw a random sample of n=70 students, and they got a mean score (denoted by
) of 
The test then boils down to the question if the score of 613 obtained by the students in the sample is statistically bigger that the "true" mean of 600.
- So the Null Hypothesis 
- The alternative would be then the opposite 
The test statistic for this type of test takes the form

and this test statistic follows a normal distribution. This last part is quite important because it will tell us where to look for the critical value. The problem ask for a 0.05 significance level. Looking at the normal distribution table, the critical value that leaves .05% in the upper tail is 1.645.
With this we can then replace the values in the test statistic and compare it to the critical value of 1.645.

<h3>since 2.266>1.645 we can reject the null hypothesis.</h3>
S = (5g -4y)/9
hope this helps
The distributive property: a(b + c) = ab + ac
12(6k + 3) + 4(7 - 5k) = 12(6k) + 12(3) + 4(7) + 4(-5k)
= 72k + 36 + 28 - 20k = 52k + 64
Answer:
5:5 (first box, pencils to pens)
7:3 (second box, coloured pencils to crayons)
The probability of picking a pen (1st box): 5/10
The probability of picking a crayon (2nd box): 3/10
Probability of picking both: 5/10*3/10 = 15/100