Answer:
The answer is
Step-by-step explanation:
Carl spent $140 in six days. He spent $20 on the first day. He spent the same amount of money during the next five days. 4a.Writ
1 answer:
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Answer:
Tina would save the same amount using either option after 20 months.
With either option, Tina would save $700.
Step-by-step explanation:
This problem can be modeled by a first order equation:
Where Tina's saved money after n months is:
S(n) = S(0) + rn, where S(0) is the money put away initially and r is how much she saves every month.
The first option is to put $500 away initially and save $10 every month, so:
The second option is to put $100 away initially and save $30 every month, so:
After how many months would Tina save the same amount using either option?
It will happen at the month n in which , so:
500 + 10n = 100 + 30n
500 - 100 = 30 - 10n
400 = 20n
20n = 400
n = 20.
Tina would save the same amount using either option after 20 months.
How much would she save with either option?
We can choose or
, since they are equal
With either option, Tina would save $700.
To solve this, you need to isolate/get the variable "x" by itself in the inequality:
2(1 - x) > 2x Divide 2 on both sides
1 - x > x Add x on both sides to get "x" on one side of the inequality
1 - x + x > x + x
1 > 2x Divide 2 on both sides to get "x" by itself
or
(x is any number less than 1/2)
[Another way you could've solved it]
2(1 - x) > 2x Distribute 2 into (1 - x)
(2)1 + (2)(-x) > 2x
2 - 2x > 2x Add 2x on both sides
2 - 2x + 2x > 2x + 2x
2 > 4x Divide 4 on both sides to get "x" by itself