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lidiya [134]
3 years ago
10

Angela has a credit score of 800 describe reasons why her score might be so high

Mathematics
1 answer:
Lapatulllka [165]3 years ago
6 0
She does not use her creator card a lot or she does not purchase many expensive items
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The ages of the people in attendance at the showing of an award-winning foreign film are shown below.
guapka [62]

Definition: A histogram visualises the distribution of data over a continuous interval or certain time period. Each bar in a histogram represents the tabulated frequency at each interval.

According to the given histogram,

0-20 years occur 15 times,

21-40 years occur 40 times,

41-60 years occur 40 times,

61-80 years occur 15 times.

This shows that the data is symmetrical and the majority of the attendees were between the ages of 21 and 60 (40 times).

Answer: correct choice is B.

5 0
3 years ago
Read 2 more answers
Emmett went to the chocolate store and bought 5 pounds of chocolate. If 2⁄3 of the chocolate was white chocolate, how many pound
AleksandrR [38]
10/3 pounds white chocolate he bought
7 0
3 years ago
Read 2 more answers
Find the value of x. Round your answer to the nearest tenth.
NikAS [45]

Answer:

In this question, we can use the Pythagorean theorem to solve for x.

11^2 + x^2 =24^2

x^2 = 24^2 -11^2

x is about 21.3

Let me know if this helps!

8 0
2 years ago
What is the lower extreme and the upper extreme of the numbers 45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100
Greeley [361]
The lower extreme is the least value in the data set and the upper extreme is the greatest value. These two values can therefore be found directly from an ordered set of data.
Lower extreme is 45
Upper extreme is 100
Good luck
7 0
3 years ago
Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =
Helen [10]

For the ODE

ty'+2y=\sin t

multiply both sides by <em>t</em> so that the left side can be condensed into the derivative of a product:

t^2y'+2ty=t\sin t

\implies(t^2y)'=t\sin t

Integrate both sides with respect to <em>t</em> :

t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C

Divide both sides by t^2 to solve for <em>y</em> :

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}

Now use the initial condition to solve for <em>C</em> :

y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}

\implies9=\dfrac4{\pi^2}(1+C)

\implies C=\dfrac{9\pi^2}4-1

So the particular solution to the IVP is

y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}

or

y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}

6 0
2 years ago
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