Question

Given 23 g of potassium nitrate per 25 g of water, what temperature should create a saturated solution?

Answer 1

Answer:

At about 51 °C

Explanation:

Hello there!

In this case, according to the attached solubility chart of potassium nitrate, our first step for this problem is to calculate the grams of this solute in 100 g given that 23 g are soluble in 25 g of water:

$\frac{23g}{25g}=\frac{x}{100g}\\\\x= \frac{23g*100g}{25g}=92g$

Thus, such solubility of 92 g in 100 g of water is exhibited at about 51 °C.

Regards!