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3 years ago

On the electromagnetic spectrum what two types of waves are microwaves between?

1 answer:

4 0

Microwaves are defined as electromagnetic radiations with a frequency ranging between 300 MHz to 300 GHz while the wavelength ranges from 1 mm to around 30 cm. The microwave radiation is commonly referred to as microwaves. They fall between the infrared radiation and radio waves in the electromagnetic spectrum. radio waves in the electromagnetic spectrum.

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If a chemist has 2.3 moles of arsenic (as) that has a molar mass of 74.92 g/mol, which would be the best way to find out how man

mr Goodwill [35]

The best way to determine the number of atoms of arsenic in the sample will be to multiply 2.3 by Avagadro's number.
This is because Avagadro's number is the number of particles one mole of any substance has, and its value is 6.02 x 10²³
If the number of moles of a substance are known, then multiplying by Avagadro's number will give the number of particles. In this case, this is 1.38 x 10²⁴.

3 0

3 years ago

Describe a polyhydroxyl alcohol.

Mademuasel [1]

With a name like poly hydroxyl alcohol, it suggests that the alcohol has more than one alcohol group. Thus any alcohol with more than one hydroxyl is a polyhydroxyl alcohol. An example that pops into mind is ethanediol (CH2OHCH2OH) this has 2 hydroxyl groups and is an alcohol, thus a polyhydroxyl alcohol

8 0

3 years ago

Suppose you heat a metal object with a mass of 31.7 g to 96.5 oC and transfer it to a calorimeter containing 100.0 g of water at

OverLord2011 [107]

Answer: The specific heat of the metal in $1.34J/g^0C$

Explanation:

$Q_{absorbed}=Q_{released}$

As we know that,

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$

where,

$m_1$ = mass of metal = 31.7 g

$m_2$ = mass of water = 100.0 g

$T_{final}$ = final temperature = $24.6^oC$

$T_1$ = temperature of metal = $96.5^oC$

$T_2$ = temperature of water = $17.3^oC$

$c_1$ = specific heat of metal= ?

$c_2$ = specific heat of water = $4.184J/g^0C$

Now put all the given values in equation (1), we get

$m_1\times c_1\times (T_{final}-T_1)=-[m_2\times c_2\times (T_{final}-T_2)]$

$-(31.7\times c_1\times (24.6-96.5)^0C)=(100.0\times 4.184\times (24.6-17.3)]$

$c_1=1.34J/g^0C$

Therefore, the specific heat of the metal in $1.34J/g^0C$

4 0

3 years ago

A solution containing HCl would likely have a high pH and a low pOH. A low pH and a high pOH. A high pH and a high pOH. A low pH

Tomtit [17]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Since we already know that HCl is an acid and acids have low pH values, it must have pH less than 7, so we can conclude that it has A low pH and A high pOH value.

So, the solution containing HCl must be the same.

That is :

A low pH and a high pOH

8 0

3 years ago

Question 1 of 10

AlexFokin [52]

The answer to that multiple choice would be A, the solution is an acid

8 0

3 years ago

Read 2 more answers