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alexira [117]
3 years ago
15

Room heaters are placed on the floor of a room; Give reason:

Physics
1 answer:
KATRIN_1 [288]3 years ago
7 0

Room heaters are placed on the floor of a room so that the air heated by it rises up and sets up the convection current in the room quickly and uniformly.

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An object moves 2.5 m. This is an example of a _______. Question 3 options: direction distance velocity speed
Hitman42 [59]
Distance, since distance represents how far something has travelled, which would be in our case 2.5m.
5 0
3 years ago
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Which of the following expressions is equivalent to the expression 2(x + 5)? x + 7 x + 10 2x + 5 2x + 10
bezimeni [28]

Answer:

d) 2x+10

Explanation:

2(x+5)\\=2x+10

6 0
4 years ago
The device that demonstrates the presence of static electricity is called a(n) _____.
galben [10]
<span>The device that demonstrates the presence of static electricity
is called a electroscope .</span>
8 0
3 years ago
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A wire of length L is wound into a square coil with 167 turns and used in a generator that operates at 60.0 Hz and 120 V rms val
Mrac [35]

Answer:

171.43m

Explanation:

First, define emf( electromotive force )-is the unit electric charge imparted by an energy source. In this case the generator.

The peak emf is:

E_p_e_a_k=\sqrt2(E_m_a_x)=\sqrt(2\times 120V)=170V

Substituting w=2\pi f and the value for peaf E gives:

Total length=4\sqrt {\frac{NE_p_e_a_k}{Bw}=4\sqrt{\frac{167\times 170}{0.041T\times 2pi \times 60.0Hz}

=171.43m

Hence, wire's length is 171.43m

8 0
3 years ago
Use the work—energy theorem to solve each of these problems. You can use Newton's laws to check your answers. Neglect air resist
andreyandreev [35.5K]

Answer:

a) It is moving at 43.15\frac{m}{s^{2}} when reaches the ground.

b) It is moving at 101.44\frac{m}{s^{2}} when reaches the ground.

Explanation:

Work energy theorem states that the total work on a body is equal its change in kinetic energy, this is:

W=K_f-K_i (1)

with W the total work, Ki the initial kinetic energy and Kf the final kinetic energy. Kinetic energy is defined as:

K=\frac{mv^2}{2} (2)

with m the mass and v the velocity.

Using (2) on (1):

W=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (3)

In both cases the total work while the objects are in the air is the work gravity field does on them. Work is force times the displacement, so in our case is weight (w=mg) of the object times displacement (d):

W=Fd=wd=mgd (4)

Using (4) on (3):

mgd=\frac{mv_f^2}{2}-\frac{mv_i^2}{2} (5)

That's the equation we're going to use on a) and b).

a) Because the branch started form rest initial velocity (vi) is equal zero, using this and solving (5) for final velocity:

v_f=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*95}

v_f=43.15\frac{m}{s^{2}}

b) In this case the final velocity of the boulder is instantly zero when it reaches its maximum height, another important thing to note is that in this case work is negative because weight is opposing boulder movement, so we should use -mgd:

-mgd=-\frac{mv_i^2}{2}

Solving for initial velocity (when the boulder left the volcano):

v_i=\sqrt{\frac{2mgd}{m}}=\sqrt{2gd}=\sqrt{2*9.8*525}

v_i=101.44 \frac{m}{s^{2}}

3 0
3 years ago
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