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Iteru [2.4K]
3 years ago
5

The logical view of a database system refers tohow a user or programmer conceptually organizes and understands the data. how the

DBMS accesses data for a certain application program. how and where the data are physically arranged and stored. how master files store data values used by more than one application program.
Computers and Technology
1 answer:
Leona [35]3 years ago
7 0

Answer: How a user or programmer conceptually organizes and understands the data.

Explanation:

  • The logical view is one of the type of view in the database system that provide some logical concept to the user of the database management system which include the state diagram, UML and the class diagram.
  • In the database system, each user posses their own logical view on the basis of the specific task and function and it also helps in maintain the database system in an organization.    

According too the given question, the logical view is basically refers to the programmers or any user is typically understand the given data and conceptually organize the data in logical manner in the database management system.

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Describe PROM, EPROM and EEPROM memories​
skelet666 [1.2K]

Answer:

Explanation:

PROM is a Read Only Memory (ROM) that can be modified only once by a user while EPROM is a programmable ROM that can be erased and reused. EEPROM, on the other hand, is a user-modifiable ROM that can be erased and reprogrammed repeatedly through a normal electrical voltage.

7 0
3 years ago
How does making a phone call differ when using: A public phone A cell phone
rosijanka [135]

Answer:

Differ in the quality of their transmission.

Explanation:

For example, when using the public phone box, wired transmission is done not wireless as in cell phones. Public phone box use electronic signals transmitted through a cable network to send voice data which are not very effective for long distance communication.

However, cell phones wirelessly send electromagnetic wave signal to a cell tower close to the caller and then the information is then transmitted to cell tower close to the receiver within a split of a second. This method of communication has much advantages.

7 0
3 years ago
A circuit contains three resistors connected in parallel. The value of R1 is 2 K , the value or R2 is 6 K , and the value of R3
mezya [45]
In a parallel connection, the voltage is same in every branch.
Now, three <span>three resistors connected in parallel.
R1 = 2k ohm
</span>R2 = 6k ohm
R3 = 10k ohm
in parallel, net resisitance  = \frac{ R_{1}R_{2}R_{3} }{R_{1}R_{2} + R_{2}R_{3} + R_{3}R_{1}}

Now, putting the values, we get, R net = 1.30 k ohm.
Ans, voltage = 100 VDC
Thus, power = \frac{ V^{2} }{R} = \frac{ 100^{2} }{1.3 k} \\ \\ where \\ k = 10^{3} 
                      = 7.69 Watt
6 0
3 years ago
You have a combination lock with three secret digits. Find the three correct digits using the following clues and enter your ans
denis-greek [22]

Answer:

021

Explanation:

021 could be your answer

6 0
2 years ago
Write a program that will read in a line of text and output the number of words in the line and the number of occurrences of eac
kherson [118]

Answer:

Here is the C++ program:

#include<iostream>  //to use input output functions

#include <algorithm>  //to use tolower() function

using namespace std;  //to identify objects like cin cout

int main() {  //start of main function

 string text;  // to hold text input

 cout<<"Enter a line of text: ";  // prompts user to enter a string

 getline(cin,text);  // reads the input string (text) from user

transform(text.begin(), text.end(), text.begin(), ::tolower);  //converts the text into lower case

 int letter[26] = {0}; //to hold the letters

 int i;  // used as a loop variable

 int words=0;  // to hold the count of words

 for(i = 0; i< text.size();i++){  // iterates through the text

 if(isalpha(text[i])&&(text[i+1]=='.'||text[i+1]==','||text[i+1]==' '))  //checks if the character at i-th index of text is a letter, and checks if i+1 index position of text is a period, comma or a space

 words++;  // adds 1 to the count of words

 if(isalpha(text[i]))  // if the character at the i-th index of text is a letter

 letter[text[i]-'a']++;  }  // counts the occurrences of each letter

 char j = text[text.size()-1];  // sets j to the last character of text

 if(j != '.' && j!= ' '&& j!=',' &&j!= '\0')  //if the last character is not a period or empty space  or comma or end of lone

 words++;  //add 1 to the count of words

 cout<<"Number of words: "<<words<<endl;  //display the number of words in the text

 for(i=0; i<26; i++)  {  //iterates 25 times

   if(letter[i]>0)  //if letter at index i is greater than 0

   cout<<(char)('a'+i)<<" : "<<letter[i]<<endl;  }} //displays each letters and its number of occurrences in the text

 

Explanation:

The program is explained in the attached document with an example.

7 0
3 years ago
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