Answer:
£42
Step-by-step explanation:
The ratio of Richard's amount to Stephen's amount is ...
R : S = 3 : 1
The ratio of Natasha's amount to Richard's amount is ...
N : R = 2 : 1 = 6 : 3
Then the ratio of all three amounts is ...
N : R : S = 6 : 3 : 1
The proportion of the total that Natasha gets is ...
6/(6+3+1) = 6/10
so she gets ...
(6/10)×£70 = £42
Natasha gets £42.
Left to right. Whatever comes first (multiplication or division) you do. This is all part of the PEMDAS/Order of operations.
Hopefully I solved your problem! :)
Um, so it's a bit awkward with this question because they actually got the x value incorrect. When they added up all the values, they got 9x - 27 = 180, but it's actually 9x + 27 = 180 because -18 + 45 is positive 27. Anyways, when you solve it correctly you get x = 17, and then you substitute it into the angles. So with 5x - 18, you are saying 5(× 17) - 18 = 67. Then with the other one you do 4(× 17) + 45 = 113. You know that x is definitely 17 because 113 + 67 = 180.
A, x=-13 or x=21.
-13 - 4 (-13+ -4) is equal to -17. Due to absolute value bars, it is now positive 17.
21-4 = 17
Answer:
See explanation
Step-by-step explanation:
1. To rewrite the expression
use exponents property
So,
2. Why ![10^{\frac{1}{3}}=\sqrt[3]{10}?](https://tex.z-dn.net/?f=10%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%3D%5Csqrt%5B3%5D%7B10%7D%3F)
Raise both sides to 10 power:
![(10^{\frac{1}{3}})^3=10^{\frac{1}{3}\cdot 3}=10^1=10\\ \\(\sqrt[3]{10})^3=10](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D10%5E%7B%5Cfrac%7B1%7D%7B3%7D%5Ccdot%203%7D%3D10%5E1%3D10%5C%5C%20%5C%5C%28%5Csqrt%5B3%5D%7B10%7D%29%5E3%3D10)
So,
![(10^{\frac{1}{3}})^3=(\sqrt[3]{10} )^3](https://tex.z-dn.net/?f=%2810%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%29%5E3%3D%28%5Csqrt%5B3%5D%7B10%7D%20%29%5E3)
3. Simplify 
Use the Quotient of Powers Property:
Then
4. Solve 
First, note that 
then
Number 
is irrational number, number 10 is rational number. The sum of irrational and rational numbers is irrational number.
5. The same as option 4.
