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VLD [36.1K]
3 years ago
11

Find the area of the circle with a circumference of 30(pie). Write your solution in terms of (pie)

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

option 3

Step-by-step explanation:

circumference = 2 \pi r\\30 \pi = 2 \pi r\\\\r = \frac{30 \pi }{2 \pi} =15mm\\\\Area = \pi r^2 = \pi 15^2 = 225 \pi  \ mm^2

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kobusy [5.1K]

Answer:

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Step-by-step explanation:

7 0
3 years ago
A+B-C=3pi then find sinA+sinB-sinC
steposvetlana [31]
The answer:
the full question is as follow:

if A+B-C=3pi, then find sinA+sinB-sinC

first, the main formula of sine and cosine are:
sinC = 2sin(C/2)cos(C/2)
sinA +sinB = 2sin[(A+B)/2]cos[(A-B)/2]

therefore: 
 sinA+sinB-sinC = 2sin[(A+B)/2]cos[(A-B)/2] - 2sin(C/2)cos(C/2)

sin[(A+B)/2] = cos(C/2)
2sin(C/2)cos(C/2) = cos[(A+B)/2
and 
A+B-C=3 pi implies A+B =3 pi + C, so 
cos[(A+B)/2] = cos [3 pi/2  + C/2]
and  with the equivalence cos (3Pi/2  + X) = sinX

sinA+sinB-sinC =  cos(C/2)+ sin(C/2) 
7 0
3 years ago
What is the factored form of 250x3 − 16?
ladessa [460]

Answer:

Step-by-step explanation:

250x^3-16

2(125x^3-8)

2[(5x)^3-(2)^3]

2(5x-3)[(5x)^2+5x*3+(2)^2]

2(5x-3)(25x^2+15x+4)

8 0
3 years ago
The width of a rectangle is 3 units less than the length. The area of the rectangle is 4 units. What is the length, in units, of
posledela
The answer is 4
To get the area you gotta multiply the length which is 4 by 1 which is the with 1•4 = 4
4 0
4 years ago
Read 2 more answers
Last homework for mathematics, mr Thompson!
Flura [38]

Answers:

  1. Have a common difference
  2. Have a common factor
  3. Have a linear first difference

============================================================

Explanation:

Linear functions, such as y = 2x+5, have a common difference. In that example, the common difference would be 2 since we add 2 to each term to get the next one. Consider when x = 1 and that leads to y = 7. Then when x = 2, we have y = 9. Then when x = 3, we have y = 11, and so on. The sequence of y values {7,9,11,...} shows we add 2 each time.

------------------

Exponential functions have us multiply the previous term by some common factor to get the next term. A sequence like {2,6,18,...} has us multiply by 3 each time and the exponential function modeling this sequence is y = 2(3)^(x-1) where x is a natural number. So this is an example showing that exponential functions have a common factor, or we can call this a common ratio.

------------------

Quadratic functions are a bit strange.

Let's consider the quadratic of y = x^2. The sequence of y values it generates is {1,4,9,16,25...} for positive integers x = 1, 2, 3, 4, 5....

Let's subtract the adjacent terms (larger - smaller)

  • 4-1 = 3
  • 9-4 = 5
  • 16-9 = 7
  • 25-16 = 9

Note the results of 3,5,7,9 are in a linear sequence (we're adding 2 to each increment value, so the next increment would be +11). We can consider this a linear first difference.

------------------

For any of these functions, I'm restricting x to be an integer and x = 1 is the smallest input possible.

6 0
3 years ago
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