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Ira Lisetskai [31]
3 years ago
9

I need hero for my exam.

Mathematics
1 answer:
elixir [45]3 years ago
8 0

Answer:

wdym by "I need a hero for my exam"

do u want someone to solve all the problems for you?

You might be interested in
PLEASE HELP!!
madam [21]

Answer:

k=2/3

Step-by-step explanation:

Step 1:

Step 1 in solving the exponential equations is re-writing the base same as other side of the equation

so,

25^{3k}=625\\=> 25^{3k}=25^2

Step 2:

Second step is equating the exponents

The rule used is:

If\ B^m=B^n\ then\ m=n

So in this case

3k=2\\k = \frac{2}{3}

So the solution is:

k=2/3 ..

3 0
3 years ago
2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe
k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and  Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

N=(25+60)+(40+60) - 60\\N= 125

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%

3 0
3 years ago
Add. 6 1/3 + 4 ¾ + 3 7/12 =
vodka [1.7K]
14 2/3 This is the answer! I know you will get this right buddy!
3 0
3 years ago
Read 2 more answers
4x + 5y = 3 2x + 3y = 1Solve by elimination
Lesechka [4]

Answer:

The solution to the system of equations is:

x = 2, and y = -1

Explanation:

Given the pair of equations:

4x + 5y = 3 ..........................................................................(1)

2x + 3y = 1............................................................................(2)

To solve this by elimination:

Multiply equation (2) by 2, to eliminate x

Equation (2) becomes

4x + 6y = 2 .........................................................................(3)

Subtract equation (1) from (3)

4x - 4x + 6y - 5y = 2 - 3

y = -1 ....................................................................................(4)

Multiply equation (1) by 3 and equation (2) by 5 to eliminate y

Equation (1) becomes

12x + 15y = 9 .......................................................................(5)

Equation (2) becomes

10x + 15y = 5 ........................................................................(6)

Subtract equation (6) from (5)

12x - 10x + 15y - 15y = 9 - 5

2x = 4

Divide both sides by 2

x = 4/2 = 2 ............................................................................(7)

From equations (7) and (4)

x = 2, and y = -1

7 0
1 year ago
How is adding mixed numbers with unlike denominators the same as adding fractions with unlike denominators? How is it different?
Sedaia [141]
To add a mixed number you must first convert it into a heavy headed fraction eg. 12/4
Then you must find a common denominator for all of the fractions like you normally do for regular addition of fractions
After you have added them you must convert the heavy headed fraction back into a mixed number by seeing how many times the numerator goes into the denominator
5 0
4 years ago
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