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3 years ago

How many flourine atoms are present in 5.3 grams of flourine sample? (note that you have to use the 3 step method)

Chemistry

1 answer:

Bingel [31]3 years ago

8 0

Answer:

1.7x10²³ Fluorine atoms are present

Explanation:

To solve this question we must know that, to find the amount of atoms of a substance from its mass, we have, as first, to convert this mass to moles using molar mass of the substance. With the moles we can find the amount of molecules using Avogadro's number. And with the formula we can know the atoms presents:

<em>Moles Fluorine (F₂, Molar mass: 37.997g/mol)</em>

5.3g * (1mol / 37.997g) = 0.139 moles F₂

<em>Molecules F₂:</em>

0.139 moles F₂ * (6.022x10²³molecules / mol) = 8.4x10²² molecules F₂

As 1 molecule of F₂ contains 2 atoms of Fluorine:

8.4x10²² molecules F₂ * 2 =

<h3>1.7x10²³ Fluorine atoms are present</h3>

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Calculation: If you have a pH of 5.5 for a weak acid with a pKa of 4.76, then is there more A- or more HA in the solution? Expla

devlian [24]

Answer:

lets set the ratio -A/HA as R:

pH = pKa + log(R,10) => pKa + log10(R)

pH = 5.5

pKa = 4.76

R => 10^(pH - 4.76)

10^(pH - 4.76) => 5.4954

Given R (-A/HA) a number bigger than 1, then the concentration of -A is bigger than HA

Explanation:

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3 years ago

Read 2 more answers

In November 1987, a massive iceberg broke loose from the antartic ice mass and floated free in the ocean. The chunk of ice was e

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<h2>Answer:</h2>

1.58 × 10∧16 pools.

<h3>Explanation:</h3>

Given:

Length of ice berg= 98 miles = 1557716 meters

Width of iceberg = 25 miles = 40233.6 meters

Thickness of iceberg = 750 ft = 230 meters

Volume of water in a swimming pool = 24,000 gallons = 90850 liters

The volume of the ice berg:

Volume = Length . width . thickness

Volume = 1557716 . 40233.6 . 230 = 1,441, 468, 016, 5248 m3 = 1,441, 468, 016, 5248 × 10 ∧3 L.

1 pool contains liters of water: 90850 liters

1,441, 468, 016, 5248 × 10 ∧3 liters contains = 1/90850 . 1,441, 468, 016, 524.8 × 10 ∧3 .

= 1.100 . 1,441, 468, 016, 5248 × 10 ∧3 L.

= 1.58 × 10∧16 pools.

Hence 1.6 × 10∧16 pools will be filled with that chunk of ice.

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3 years ago

Calculate the theoretical density (in g/cm3) of copper (Cu), given that it has the FCC structure. The atomic weight of Cu is 63.

sasho [114]

Answer:

8.937g/cm³

Explanation:

To answer this question we need to know that, in 1 unit FCC cell you have:

Edge length = √8 * R

<em>Volume = 8√8 * R³</em>

<em>And there are 4 atoms per unit cell</em>

<em />

<em>Mass of 4 atoms in g:</em>

4 atom * (1mol / 6.022x10²³atom) * (63.55g / mol) = 4.221x10⁻²²g

<em />

<em>Volume in cm³:</em>

0.1278nm * (1x10⁻⁷cm / 1nm) = 1.278x10⁻⁸cm

Volume = 8√8 * (1.278x10⁻⁸cm)³

Volume = 4.723x10⁻²³cm³

And density is:

4.221x10⁻²²g / 4.723x10⁻²³cm³ =

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4 years ago

When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a

AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

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3 years ago

Which is an example of a base?a(lemon juice b(baking soda c(an insolator d( water

bija089 [108]

Answer:

b) Baking soda

Explanation:

Baking soda is sodium hydrogen carbonate, NaHCO₃.

It reacts with water according to the equation

NaHCO₃ + H₂O ⇌ H₂CO₃ + NaOH

Thus, baking soda is a base because it increases the concentration of hydroxide ions in water.

<em>Water</em> is <em>neutral</em>.

<em>Lemon juice</em> is an <em>acid</em> because it contains citric acid.

An <em>insulator </em>is a substance that does not conduct electricity. Insulators are <em>neither acidic nor basic</em>.

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3 years ago

How many flourine atoms are present in 5.3 grams of flourine sample? (note that you have to use the 3 step method)​

How many flourine atoms are present in 5.3 grams of flourine sample? (note that you have to use the 3 step method)