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3 years ago

Which is an example of a base?a(lemon juice b(baking soda c(an insolator d( water

Chemistry

1 answer:

bija089 [108]3 years ago

3 0

Answer:

b) Baking soda

Explanation:

Baking soda is sodium hydrogen carbonate, NaHCO₃.

It reacts with water according to the equation

NaHCO₃ + H₂O ⇌ H₂CO₃ + NaOH

Thus, baking soda is a base because it increases the concentration of hydroxide ions in water.

Water is neutral.

Lemon juice is an acid because it contains citric acid.

An insulator is a substance that does not conduct electricity. Insulators are neither acidic nor basic.

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230g sample of a compound contains 136.6g carbon, 26.4g hydrogen, and 31.8g nitrogen. What is masspercentif oxygen

natulia [17]

Answer:

15.3 %

Explanation:

Step 1: Given data

Mass of the sample (ms): 230 g

Mass of carbon (mC); 136.6 g

Mass of hydrogen (mH): 26.4 g

Mass of nitrogen (mN): 31.8 g

Step 2: Calculate the mass of oxygen (mO)

The mass of the sample is equal to the sum of the masses of all the elements.

ms = mC + mH + mN + mO

mO = ms - mC - mH - mN

mO = 230 g - 136.6 g - 26.4 g - 31.8 g

mO = 35.2 g

Step 3: Calculate the mass percent of oxygen

%O = (mO / ms) × 100% = (35.2 g / 230 g) × 100% = 15.3 %

6 0

3 years ago

How much silver is produced is 15.00 grams of cu is added to the solution of excess silver nitrate?

il63 [147K]

First write out the balanced equation. 3Cu+2Ag(NO3)3=2Ag+3Cu(NO3)2
Then convert copper from grams to moles
15 g*1 mol cu/63.54 g= 15/63.54 mol cu
Then use the mole ratio to convert Moles Cu to Moles Ag
15/63.54 moles Cu* 2 moles Ag/3 moles Cu
The final awnser is (15*2)/(63.54*3) moles Ag =0.157 moles Ag. If the question wants the answer in grams, convert from moles Ag to grams Ag.
0.157 moles Ag*107.87 g Ag/ mol Ag=16.98 g Ag

6 0

3 years ago

Treatment of 2-hexanone with naoch2ch3 followed by ch3br affords compound x (c7h14o) as the major product. x shows a strong abso

VashaNatasha [74]

The given ketone when reacted with base gave enolate, the enolate formed due to loss of methylene proton next to carbonyl group. Enolate when treated with methyle Bromide gave alpha substituted product.

Strong absorption around 1713 cm⁻¹ in IR spectrum confirms the presence of Carbonyl group.

The product along with ¹H-NMR values is given below,

8 0

4 years ago

You are a doctor examining a bone sample taken from a patient with weak bones you find out the bone tissue contains many small p

Contact [7]

The bone tissue contains many small pauses this is most likely caused by osteoporosis.

<h3>What is osteoporosis?</h3>

Osteoporosis is a health condition that weakens bones, making them fragile and more likely to break.

Osteoporosis causes bones to become weak and brittle — so brittle that a fall or even mild stresses such as bending over or coughing can cause a fracture.

Osteoporosis-related fractures most commonly occur in the hip, wrist or spine.

Bone is living tissue that is constantly being broken down and replaced.

Hence, the bone tissue contains many small pauses this is most likely caused by osteoporosis.

Learn more about the osteoporosis here:

brainly.com/question/7246059?referrer=searchResults

#SPJ1

7 0

2 years ago

A salt contains only magnesium and one of the halide ions. A 0.0776-g sample of the salt was dissolved in water, and an excess o

sdas [7]

Answer:

The formula of the magnesium halide is MgF₂

Explanation:

All halides, X, produce a salt with Mg with the formula:

MgX₂

-There are 2 moles of the halide ion per mole of Mg-

With the mass of the MgSO₄ we can find moles of magnesium sulfate = Moles Mg.

With moles of Mg we can know the moles of the halide -1 mole Mg = 2 moles of Halide-

And we can find the mass of Mg in the 0.0776g sample. Subtracting we can find the mass of the halide and, with the mass and moles of the halide we can find its molecular weight and its identity:

Moles MgSO₄ -Molar mass: 120.366g/mol- = Moles Mg:

0.150g * (1mol / 120.366g) = 1.2462x10⁻³ moles Mg

Moles halide:

1.2462x10⁻³ moles Mg * 2 = 2.4924x10⁻³ moles Halide

Mass Mg -Molar mass: 24.305g/mol:

1.2462x10⁻³ moles Mg * (24.305g / mol) = 0.0303g Mg

Mass halide:

0.0776g - 0.0303g Mg = 0.0473g

Molecular weight of the halide:

0.0473g / 2.4924x10⁻³ moles =

18.98g/mol

This molecular weight is the molecular weight of Fluoride ion, F⁻,

<h3>The formula of the magnesium halide is MgF₂</h3>

6 0

3 years ago