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LenKa [72]
3 years ago
14

Which equation(s) represents a nonproportional relationship? Select all that apply

Mathematics
1 answer:
Wewaii [24]3 years ago
8 0
The answer is -2-4
Don’t click on the other comment, that link is a hack
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Divide both sides by l. Hope this helps! :D
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1. Eight people work in an office. They are paid hourly rates of 12£,15£,15£,14£,14£,13£,14£,13£
bearhunter [10]

Answer:

mean=110/8 =13.75 pounds;  median=14 pounds; mode=14 pounds; average=13.75 pounds

Step-by-step explanation:

mean=add all the numbers together to get total then divide that total by the number of amounts present 12, 15, 15, 14, 14, 13, 14, 13 =110, then 110/8=13.75 pounds

mode=arrange amounts in order (smallest to largest), then determine which amount appears more than the other amounts 12, 13, 13, 14, 14, 14, 15, 15 =14 appears the most

median=organize numbers from smallest to greatest, count how many there are, then determine which number appears in the middle of all of them 12, 13, 13, 14, 14, 14, 15, 15 = there are 8 numbers present but 14 is in the middle; answer =14

average= take total of mean, then divide it by the number of amounts that appear 110/8 =13.75

8 0
3 years ago
Which of the following amounts is greater than 4 yards? Select all that apply.
Bezzdna [24]

Answer:

is c

Step-by-step explanation:

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3 years ago
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The number of minutes taken for a chemical reaction if f(t,x). it depends on the temperature t degrees celcius, and the quantity
tatiyna
Hello,

Just for the fun, it's been a long time for that.

f(30,5)=50\\

f(t+3,x)=f(t,x)-5\ ==\textgreater \dfrac{f(t+3,x)-f(t,x)}{3}= -\frac{5}{3} \\

f(t,x+2)=f(t,x)-3\ ==\textgreater\dfrac{f(t,x+2)-f(t,x)}{2}= -\frac{3}{2} \\

f(t+\Delta t,\Delta x)=f(f,t)+ \dfrac{\partial{f(t,x)}}{\partial{t}} *\Delta t+ \dfrac{\partial{f(t,x)}}{\partial{x}} *\Delta x\\

f(33,4)\approx f(30,5)- \dfrac{5}{3} *3-\dfrac{3}{2}*(-1)= 50- 5+1.5=46.5\\




6 0
3 years ago
1/2(6y-8)+4y=10-2y+4
r-ruslan [8.4K]

Answer:

y=2

Step-by-step explanation:

hope this helps

3 0
3 years ago
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