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rosijanka [135]
4 years ago
5

About how many times can you use the plant food on the

Mathematics
1 answer:
siniylev [52]4 years ago
3 0

Answer:

25 times is what I would say. Because if it is 600 square feet so it should be enough room for 25 seeds.so the answer is.....

D. 25

Step-by-step explanation:

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A square is cut out of a copper sheet. Two straight scratches on the surface of the square intersect forming an angle. The squar
ArbitrLikvidat [17]

Answer:

(c) Stay the same

Step-by-step explanation:

Final angle will be same as initial angle. But length of lines will increase in both direction proportionally.

However any normal curve(closed or open ) will remain proportional to initial one. It is like a Zooming or magnifying of object.

5 0
4 years ago
Anyone know the answer??
vlabodo [156]

Answer:

I believe that the correct answer is 7.

Step-by-step explanation:

Is tht good homie

4 0
3 years ago
Read 2 more answers
HELP ASAPPPPP!!!! PLZ
disa [49]

Answer:

y=1/2x+2

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ME OUT ASAP! I WOULD REALLY APPRECIATE IT AND GOD BLESS
77julia77 [94]
To approximate the P(x<27) we need to find the z-score of the data, this will be given by:
z=(x-μ)/σ
where:
μ-mean
σ-standard deviation
x=27, μ=32, σ=4
z=(27-32)/4
z=-5/4
z=-1.25
thus
P(x<27)=P(z<-1.25)
=0.1056
=10.56%

Answer: 10.56%
5 0
4 years ago
A sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's p
Grace [21]

Answer:

Yes, we have sufficient evidence at the 0.02 level to support the company's claim.

Step-by-step explanation:

We are given that a sample of 1500 computer chips revealed that 32% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature claimed that above 29% do not fail in the first 1000 hours of their use.

Let Null Hypothesis, H_0 : p \leq 0.29  {means that less than or equal to 29% do not fail in the first 1000 hours of their use}

Alternate Hypothesis, H_1 : p > 0.29  {means that more than 29% do not fail in the first 1000 hours of their use}

The test statics that will be used here is One-sample proportions test;

          T.S. = \frac{\hat p -p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = proportion of chips that do not fail in the first 1000 hours of their use = 32%

            n = sample of chips = 1500

So, <u>test statistics</u> = \frac{0.32-0.29}{\sqrt{\frac{0.32(1-0.32)}{1500} } }

                              = 2.491

<em>Now, at 0.02 level of significance the z table gives critical value of 2.054. Since our test statistics is more than the critical value of z so we have sufficient evidence to reject null hypothesis as it fall in the rejection region.</em>

Therefore, we conclude that more than 29% do not fail in the first 1000 hours of their use which means we have sufficient evidence at the 0.02 level to support the company's claim.

7 0
4 years ago
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