Answer:
Firstly find the area of the square and then the area of the two triangles and then plus it. That's what I think I tried
Answer:(9y-7)(9y+7)
Step-by-step explanation:
81y^2-49
=(9y)^2-(7)^2
=(9y-7)(9y+7)
Answer:

Step-by-step explanation:
Assuming a mean of $204 per night and a deviation of $55.
a. What is the probability that a hotel room costs $225 or more per night (to 4 decimals)?
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean"
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Let X the random variable that represent the cost per night at the hotel, and for this case we know the distribution for X is given by:
Where
and 
And let
represent the sample mean, the distribution for the sample mean is given by:

We are interested on this probability

And the best way to solve this problem is using the normal standard distribution and the z score given by:

If we apply this formula to our probability we got this:


And we can find this probability on this way:

Answer:
Option C. 
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system of equations by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The intersection point is (1,3)
see the attached figure
therefore
The solution of the system of equations is

Find the difference

Answer:
69.5%
Step-by-step explanation:
A feature of the normal distribution is that this is completely determined by its mean and standard deviation, therefore, if two normal curves have the same mean and standard deviation we can be sure that they are the same normal curve. Then, the probability of getting a value of the normally distributed variable between 6 and 8 is 0.695. In practice we can say that if we get a large sample of observations of the variable, then, the percentage of all possible observations of the variable that lie between 6 and 8 is 100(0.695)% = 69.5%.